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Vlad [161]
3 years ago
7

Calculate the percentage by mass of lead in pbco3.

Chemistry
2 answers:
Sonja [21]3 years ago
7 0

Answer:

The correct answer is d.

Explanation:

Step 1: First we must obtain the molecular weight of PbCO_{3} and Pb.

PM_{PbCO_{3} } = 267,21 \frac{g}{mol}

PM_{Pb} = 207,2 \frac{g}{mol}

Step 2: We can now calculate the percentage of lead in a PbCO_{3} molecule by stating a simple rule of three:

PM_{PbCO_{3} } -->    100%.

PM_{Pb}              -->    X

%Pb = \frac{PM_{Pb}}{ PM_{PbCO_{3} }} * 100%

%Pb = \frac{207.2 \frac{g}{mol}}{267.21 \frac{g}{mol}} * 100%

%Pb = 77,54 %

Have a nice day!

nignag [31]3 years ago
5 0
Pb/pbco3*100
207/207+12+48
207/267*100
=77.53%
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