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3 years ago

How many moles of methanol are required to produce 4.19 moles of water

Chemistry

1 answer:

Harrizon [31]3 years ago

6 0

Explanation:

every two moles of methanol will need three moles of oxygen gas and products 2 miles of carbon dioxide and 4 miles of water

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3 years ago

Read 2 more answers

For the reaction

azamat

Answer:

Mass = 5.56 g

Explanation:

Given data:

Mass of Cl₂ = 4.45 g

Mass of NaCl produced = ?

Solution:

Chemical equation:

2Cl₂ + 4NaOH → 3NaCl + NaClO₂ + 2H₂O

Number of moles of Cl₂:

Number of moles = mass/molar mass

Number of moles = 4.45 g/ 71 g/mol

Number of moles = 0.063 mol

Now we will compare the moles of Cl₂ with NaCl.

Cl₂ : NaCl

2 : 3

0.063 : 3/2×0.063 =0.095 mol

Mass of NaCl:

Mass = number of moles × molar mass

Mass = 0.095 mol × 58.5 g/mol

Mass = 5.56 g

7 0

2 years ago

Iron(III) sulfide reacts with hydrochloric acid to produce hydrogen sulfide and iron(II) chloride. Wright the formula equation f

NeX [460]

Answer:

Fe2S3 + 4HCl —> 2H2S + 2FeCl2 + S

Explanation:

From the question, we were told that:

Iron(III) sulfide reacts with hydrochloric acid to produce hydrogen sulfide and iron(II) chloride.

Please note that elemental sulphur is produced along with this reaction. The equation for the reaction is given below:

Fe2S3 + HCl —> H2S + FeCl2 + S

Now, we can balance the equation as shown below:

There are 3 atoms of S on the left side of the equation and 2 atoms on the right. It can be balance by putting 2 in front of H2S as shown below:

Fe2S3 + HCl —> 2H2S + FeCl2 + S

Now, we have 4 atoms of H on the right side and 1atom on the left side. It can be balance by putting 4 in front of HCl as shown below:

Fe2S3 + 4HCl —> 2H2S + FeCl2 + S

Also, there are 4 atoms of Cl on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of FeCl2 as shown below:

Fe2S3 + 4HCl —> 2H2S + 2FeCl2 + S

Now, we can see that the equation is balanced

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3 years ago