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OleMash [197]
3 years ago
11

Determine the unknown mineral using the information given below. Be sure to use significant figure rules when doing calculations

. Mass is shown on the triple beam. Scale Test Mineral Mineral H. Density, g/cc 10 diamond tellurium 2 2.07 9 corundum galena 2.5 7.58 8 topaz anglesite 2.5 - 3 6.4 7 quartz chalcocite 2.5 - 3 5.6 6 feldspar copper 2.5 - 3 9.0 5 apatite gold 2.5 - 3 19.3 4 fluorite silver 2.5 - 3 10.5 3 calcite arsenic 3.5 5.7 2 gypsum barite 3 - 3.5 4.4 1 talc dolomite 3.5 - 4 2.9 platinum 4.5 21.5 willemite 5.5 4.0 magnetite 6 5.18 pyrite 6 - 6.5 5.02 pyrolusite 6 - 6.5 5.0 cassiterite 6.5 6.9 diamond 10 3.52 Volume of water displaced = 0.175 L Mass: g Density. g/cm³ Hardness: = - Determine the unknown mineral. Unknown mineral:
Chemistry
1 answer:
Mademuasel [1]3 years ago
8 0

Answer:

Mass: 981.0 g

Density: 5.61 g/cm^3

Hardness: = 2.5 - 3

Unknown material: Chalcocite

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Calculate the energy in joules and calories required to heat 25.0 g of water from 12.5C to 25.7C
Alex Ar [27]
The heat (Q) required to raise the temp of a substance is:<span>Q=m∗Cp∗ΔT</span><span> where m is the mass of the object (25.0g in this case), Cp is the specific heat capacity of the substance (for water Cp = 1.00cal/gC, or 4.18J/gC,
and Dt is the change in temp.
You'll have to solve this twice, once with the Cp in calories, and once with the Cp in joules.
</span><span>1380.72 Joules</span>
8 0
3 years ago
The student adds 0.0010 mol of NaOH(s) to solution Y, and adds 0.0010 mol of NaOH(s) to solution Z. Assume that the volume of ea
julia-pushkina [17]

Answer:

The answer is in the explanation.

Explanation:

A buffer is defined as the aqueous mixture of a weak acid and its conjugate base or vice versa. Buffers are able to avoid the pH change of a solution when strong acid or bases are added (As NaOH).

Based on the experiment, it is possible that the solution Z was a buffer and Y another kind of solution. For this reson, pH of the solution Y changes much more than the pH of solution Z changes despite the amount of NaOH added is the same in both solutions.

6 0
3 years ago
Which phenomenon best explains the miscibility of heptane (CH3CH2CH2CH2CH2CH2CH3) in pentane (CH3CH2CH2CH2CH3)
Nuetrik [128]

The phenomenon that best explains the miscibility of heptane in pentane is that both are non-polar compounds.

<h3>Solubility of compounds</h3>

Solubility is defined as the ability of a solute or substance to dissolve in a given solvent and at a particular temperature.

Heptane is a straight-chain alkane hydrocarbon that contains 7 carbon atoms. It is a non polar solvent.

Pentane is also a straight-chain alkane hydrocarbon that contains 5 carbon atoms. It is also a non- polar solvent.

Both pentane and heptane are non-polar because the atoms in their molecules share electrons equally. They are able to dissolve each other because they are alike.

Learn more about solubility here:

brainly.com/question/23946616

6 0
2 years ago
What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium fluoride, LiF, (gram-formula mass =2
denis23 [38]
The answer is (1) 1.3 M. The first thing you need to do is to convert the unit of gram to mole. The mol number of LiF is 52/26=2 mol. Then using the volume to calculate the molarity: molarity=2/1.5=1.3 M.
5 0
4 years ago
Give the formulas of the compounds in each set (a) lead(l|) oxide and lead(lV) oxide; (b) lithium nitride, lithium nitrite, and
Ivanshal [37]

<u>Answer:</u>

<u>For a:</u> The formula of lead (II) oxide and lead (IV) oxide is PbO\text{ and }PbO_2 respectively.

<u>For b:</u> The formula of lithium nitride, lithium nitrite and lithium nitrate is Li_3N,LiNO_2\text{ and }LiNO_3 respectively.

<u>For c:</u> The formula of Strontium hydride and strontium hydroxide is SrH_2\text{ and }Sr(OH)_2 respectively.

<u>For d:</u> The formula of magnesium oxide and manganese (II) oxide is MgO\text{ and }MnO respectively.

<u>Explanation:</u>

All the given compounds are ionic compounds. This means that between the atoms complete sharing of electrons takes place.

  • <u>For a:</u>

Lead is the 82th element of periodic table having electronic configuration of [Xe]4f^{14}5d^{10}6s^26p^2.

To form Pb^{2+} ion, this element will loose 2 electrons and to form Pb^{4+} ion, this element will loose 4 electrons.

Oxygen is the 8th element of periodic table having electronic configuration of [He]2s^22p^4.

To form O^{2-} ion, this element will gain 2 electrons.

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for lead (II) oxide is PbO and for lead (IV) oxide is PbO_2

Thus, the formula of lead (II) oxide and lead (IV) oxide is PbO\text{ and }PbO_2 respectively.

  • <u>For b:</u>

Lithium is the 3rd element of periodic table having electronic configuration of [He]2s^1.

To form Li^{+} ion, this element will loose 1 electron.

Nitrogen is the 7th element of periodic table having electronic configuration of [He]2s^22p^3.

To form N^{3-} ion, this element will gain 3 electrons.

Nitrite ion is a polyatomic ion having chemical formula of NO_2^{-}

Nitrate ion is a polyatomic ion having chemical formula of NO_3^{-}

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for lithium nitride is Li_3N, for lithium nitrite is LiNO_2 and for lithium nitrate is LiNO_3

Thus, the formula of lithium nitride, lithium nitrite and lithium nitrate is Li_3N,LiNO_2\text{ and }LiNO_3 respectively.

  • <u>For c:</u>

Strontium is the 38th element of periodic table having electronic configuration of [Kr]5s^2.

To form Sr^{2+} ion, this element will loose 2 electrons.

Hydrogen is the 1st element of periodic table having electronic configuration of 1s^1.

To form H^{-} ion, this element will gain 1 electron and is named as hydride ion.

Hydroxide ion is a polyatomic ion having chemical formula of OH^{-}

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for strontium hydride is SrH_2 and for strontium hydroxide is Sr(OH)_2

Thus, the formula of Strontium hydride and strontium hydroxide is SrH_2\text{ and }Sr(OH)_2 respectively.

  • <u>For d:</u>

Magnesium is the 12th element of periodic table having electronic configuration of [Ne]3s^2.

To form Mg^{2+} ion, this element will loose 2 electrons.

Manganese is the 25th element of the periodic table having electronic configuration of [Ar]3d^54s^2

To form Mn^{2+} ion, this element will loose 2 electrons.

Oxygen is the 8th element of periodic table having electronic configuration of [He]2s^22p^4.

To form O^{2-} ion, this element will gain 2 electrons.

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for magnesium oxide is MgO and for manganese (II) oxide is MnO.

Thus, the formula of magnesium oxide and manganese (II) oxide is MgO\text{ and }MnO respectively.

7 0
3 years ago
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