A drop of indicator solution is added to the titration at the start; when the color changes the endpoint has been reached.
Answer:
0.00944
Explanation:
Xenon mass number on the periodic table: 131.29
Oxygen mass number: 16.00
Add them to find the molar mass of xenon trioxide: 131.29+3(16) = 179.29g/mol
Convert this to moles
The amount, in grams, of N that the sample will contain will be 2.1 grams.
<h3>Stoichiometric mass ratio</h3>
According to the problem. the mass ratio of H and N in ammonia is 4.7:1.
In other words, every 4.7 grams of H in ammonia must have 1 gram of N.
Now, in a particular ammonia sample, 10 grams of H is present.
The amount of N present can be calculated from the standard mass ratio.
4.1 grams H = 1 gram N
10 grams H = x
4.1x = 1 x 10
x = 10/4.1
x = 2.1 grams
Thus, the mass of nitrogen in the ammonia sample will be 2.1 grams.
More on mass ratios can be found here: brainly.com/question/14577772
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To convert from Kp to Kc, you need this formula---> Kp= Kc (RT)^Δn, where Δn= gas moles of product- gas moles of reactants. since you did not give a reaction formula, I can't calculate Δn. but all once you find it out. just plug it.
Kp= Kc (RT)^Δn------------------> Kc= Kp/[(RT)^Δn]
Kp= 5.23
R= 0.0821
T= 191 C= 464 K
Δn= ?
Kc= 5.23/ (0.0821 x 464)^Δn= ???
Answer:
I'd say "a" because not everything with plants and animals is perfectly organized together nothing ever is.
