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3 years ago

Solve the system thank you

Mathematics

1 answer:

Lunna [17]3 years ago

6 0

Answer:

infinite solutions

Step-by-step explanation:

replace x with 3y + 9 in the second equation

9 - (3y + 9) = -3y ➡ 9 -3y -9 = -3y ➡9-9 = 3y-3y ➡ 0 = 0

this means whatever numver you write instead of y there will be a solution.

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What is the value of X?

matrenka [14]

The two given angles are vertical angles and equal each other:

3x + 50 = 6x -10

Now solve for x:

Subtract 3x from both sides:

50 = 3x -10

Add 10 to both sides:

60 = 3x

Divide both sides by 3

X = 20

5 0

3 years ago

A positive number is<br> A negative number is

marysya [2.9K]

Answer:

A positive number is the opposite of a negative number witch is negative

ex: 1,2,3,4,5,6,7,8,9

A negative number is the opposite of a positive number

ex: -1,-2,-3,-4,-5,-6,-7,-8,-9

6 0

3 years ago

2.02b + 4.30 = 2.00b + 6.30

bonufazy [111]

Answer: b = 100

Step-by-step explanation:

simplifying

2.02b + 4.30 = 2.00b + 6.30

reorder the terms:

4.30 + 2.02b = 2.00b + 6.30

reorder the terms:

4.30 + 2.02b = 6.30 + 2.00b

solving

4.30 + 2.02b = 6.30 + 2.00b

solving for variable 'b'.

move all terms containing b to the left, all other terms to the right.

add '-2.00b' to each side of the equation.

4.30 + 2.02b + -2.00b = 6.30 + 2.00b + -2.00b

combine like terms: 2.02b + -2.00b = 0.02b

4.30 + 0.02b = 6.30 + 2.00b + -2.00b

combine like terms: 2.00b + -2.00b = 0.00

4.30 + 0.02b = 6.30 + 0.00

4.30 + 0.02b = 6.30

add '-4.30' to each side of the equation.

4.30 + -4.30 + 0.02b = 6.30 + -4.30

combine like terms: 4.30 + -4.30 = 0.00

0.00 + 0.02b = 6.30 + -4.30

0.02b = 6.30 + -4.30

combine like terms: 6.30 + -4.30 = 2

0.02b = 2

divide each side by '0.02'.

getting: b = 100

6 0

3 years ago

Factor the following expression completely: 3x^2+9x+6

ArbitrLikvidat [17]

Answer:

The answer is 3(+1)(+2)

7 0

3 years ago

Read 2 more answers

HELP ME <br> solve for the right triangle

VikaD [51]

Answer:

see explanation

Step-by-step explanation:

Using the cosine and tangent ratios in the right triangle

cos41° = $\frac{adjacent}{hypotenuse}$ = $\frac{VW}{VX}$ = $\frac{7}{VX}$

Multiply both sides by VX

VX × cos41° = 7 ( divide both sides by cos41° )

VX = $\frac{7}{cos41}$ ≈ 9.3

-----------------------------------------------------------------------

tan41° = $\frac{opposite}{adjacent}$ = $\frac{WX}{VW}$ = $\frac{WX}{7}$

Multiply both sides by 7

7 × tan41° = WX, thus

WX ≈ 6.1

-------------------------------------------------------------------------

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180° for ∠ X

∠ X = 180° - (90 + 41)° = 180° - 131° = 49°

3 0

3 years ago