Let
. The gradient of
at the point (1, 0, 0) is the normal vector to the surface, which is also orthogonal to the tangent plane at this point.
So the tangent plane has equation

Compute the gradient:

Evaluate the gradient at the given point:

Then the equation of the tangent plane is

You got all of them correct!! Nice job :)
Answer:
1
Step-by-step explanation:
all you do is multiple then devide
The answer is B. you multiply 300 and 15% and it gets you 45 that’d save you money compared to the second incentive