if y-6 > 10, and 16-6 = 10, then y > 16 since 17-6 = 11, which is greater than 10. Any number greater than 16 can fulfil this inequality.
'll use the binomial approach. We need to calculate the probabilities that 9, 10 or 11
<span>people have brown eyes. The probability that any one person has brown eyes is 0.8, </span>
<span>so the probability that they don't is 1 - 0.8 = 0.2. So the appropriate binomial terms are </span>
<span>(11 C 9)(0.8)^9*(0.2)^2 + (11 C 10)(0.8)^10*(0.2)^1 + (11 C 11)(0.8)^11*(0.2)^0 = </span>
<span>0.2953 + 0.2362 + 0.0859 = 0.6174, or about 61.7 %. Since this is over 50%, it </span>
<span>is more likely than not that 9 of 11 randomly chosen people have brown eyes, at </span>
<span>least in this region. </span>
<span>Note that (n C r) = n!/((n-r)!*r!). So (11 C 9) = 55, (11 C 10) = 11 and (11 C 0) = 1.</span>
Answer:
star
Step-by-step explanation:
Answer:
8 percent or .8
Step-by-step explanation:
Have a great day
The d value is going to be -3 because you have to compute the differences of all the adjacent terms. 2-5=-3 -1-2=-3 -4-(-1)=-3 -7-(-4)=-3 The difference between all the adjacent terms is the same and equal to -3
