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Gnoma [55]
3 years ago
11

How do I solve for b-9-b=-18

Mathematics
1 answer:
Eva8 [605]3 years ago
5 0

Answer:

no solutions

Step-by-step explanation:

b-9-b=-18

Combine like terms

0b -9 = -18

-9 = -18

This is never true, so there are no solutions

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Someone please help me quickly i will give brainlyist
scZoUnD [109]

(16,5) it should be

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im deeply sorry if this is wrong.

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The following system of equations is _____.
hoa [83]
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3 0
3 years ago
Nick billups is paid a salary of $ 900 a month, a 2 % commission on all sales, and 1.8 % more on monthly sales over $ 17,500. In
Trava [24]
June :
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5 0
3 years ago
Read 2 more answers
I WILL GIVE YOU BRAINLIEST, AND 30 POINTS SO PLEASE HELP ME, IT'S URGENT!
IRINA_888 [86]

Answer:

<em>Answer is option</em><em> </em><em>b</em><em>)</em><em> </em>

<em>{(x - 3)}^{2}  +  {(y - 4)}^{2}  = 400</em>

<em>Your</em><em> </em><em>guess</em><em> </em><em>was</em><em> </em><em>right</em><em>.</em>

Step-by-step explanation:

the \: question \: states \: that \:  \\ distance \: between \: two \: points \: is \: 20 \: units \:  \\ and \: the \: two \: points \: are \: (x,y) \:  \: and \:  \: (3 ,- 4) \\ distance \: formula \\  =   \sqrt{ {(x1 - x2) }^{2} +  {(y1 - y2)}^{2}  }  \\ on \: substituting \: the \: values \: in \: formula \\ 20 =  \sqrt{ {(x - 3)}^{2} +  {(y - ( - 4))}^{2}  }  \\ 20 =  \sqrt{ {(x - 3)}^{2} +  {(y + 4)}^{2}  }  \\ now \: squaring \: on \: both \: sides \\ 400 =  {(x - 3)}^{2}  +  {(y + 4)}^{2}  \\ hence \: the \: answer \: is \: option \: b)

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

6 0
3 years ago
A fish store received a shipment of 246 goldfish. The owner of the store arranged the fish into small tanks of 8 fish per tank.
saw5 [17]

Answer:

he would need 31 tanks

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Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
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