Answer:
B. 745 gallons
Step-by-step explanation:
<em><u>4 quarts = 1 gallon</u></em>
There are may ways to solve this, the easiest way is to divide the number of quarts by 4 (there are 4 quarts in a gallon).
2980 quarts /4 quarts = 745 gallons
We know that
[volume of the similar prism]=10*5*5----> 250 in³
volume original prism=16 cm³
1 in³---------> 16.3871 cm³
X----------> 16
x=16/16.3871------> x=0.9764 in³
[volume of the similar prism]=[scale factor]³*[volume original prism]
[scale factor]³=[volume of the similar prism]/[volume original prism]
[scale factor]³=[250]/[0.9764]------> 256.05
scale factor=∛256.05-------> 6.35
<span>the dimensions of the original prism are
1 in-----> 2.54 cm
</span>length 10 in/6.35-------> 1.57 in*2.54 cm/in-----> 4 cm
<span>width 5 in/6.35---------> 0.79 in*2.54 cm/in-----> 2 cm
</span><span>height 5 in/6.35--------> 0.79 in*2.54 cm/in----> 2 cm</span>
This is a probablity question
there are 3 slots, 26 letters of the alphabet
so in the first slot, we have 26 possible letters
2nd slot, we have 25 possible letters (we used one for the first slot)
3rd slot, we have 24 possible letters, (we used 2 for first and 2nd slot)
so in total, we have 26*25*24 or 15600 different 3 letter initials with no repeated letters
<span>To explain how these values are related, take the second value (625) and multiply it by 1/100, or in decimal form, 0.01. This is the equivalent of moving the decimal point two spaces to the left, which will give a result of 6.25. (625 * 0.01 = 6.25). This shows that the two values are 100 times different than each other.</span>
Check the picture below.
so the <u>triangular prism</u> is really 3 rectangles and two triangles stacked up to each other at the edges, so if we simply get the area of each figure individually and sum them up, that's the area of the prism.
let's notice, the triangles have a base of 2.4 and a height/altitude of 1.
![\bf \stackrel{\textit{2 triangles's area}}{2\left[ \cfrac{1}{2}(2.4)(1) \right]}~~+~~\stackrel{\textit{right rectangle}}{(2\cdot 1.5)}~~+~~\stackrel{\textit{left rectangle}}{(2\cdot 1.7)}~~+~~\stackrel{\textit{bottom rectangle}}{(2\cdot 2.4)} \\\\\\ 2.4+3+3.4+4.8\implies 5.4+8.2\implies 13.6](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7B2%20triangles%27s%20area%7D%7D%7B2%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%282.4%29%281%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bright%20rectangle%7D%7D%7B%282%5Ccdot%201.5%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bleft%20rectangle%7D%7D%7B%282%5Ccdot%201.7%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bbottom%20rectangle%7D%7D%7B%282%5Ccdot%202.4%29%7D%20%5C%5C%5C%5C%5C%5C%202.4%2B3%2B3.4%2B4.8%5Cimplies%205.4%2B8.2%5Cimplies%2013.6)