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3 years ago

Complete the equation, and tell which property you used. 8 x (14+7) = _________+ (8 x 7)

Mathematics

1 answer:

melamori03 [73]3 years ago

8 0

By distributive property, 8 x (14 + 7) = (8 x 14) + (8 x 7)

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6x+7y=4x+4y6x+7y=4x+4y6, x, plus, 7, y, equals, 4, x, plus, 4, y Complete the missing value in the solution to the equation. (((

Dmitrij [34]

Answer:

<h3>The missing value in the given solution is x=6</h3><h3>Therefore the solution is (6,-4)</h3>

Step-by-step explanation:

Given equation is $6x+7y=4x+4y\hfill (1)$

<h3>To find the missing value in the solution to the equation :</h3>

Let missing value in the solution be x
Then the solution of the given equation is (x,-4)

Substitute the value of y=-4 in the given equation (1) we get

$6x+7(-4)=4x+4(-4)$

$6x-28=4x-16$

$6x-28-(4x-16)=4x-16-(4x-16)$

$6x-28-4x+16=4x-16-4x+16$ ( adding the like terms )

$2x-12=0$

$2x=12$

$x=\frac{12}{2}$

Therefore x=6

<h3>Therefore the missing value in the given solution is x=6</h3><h3>Therefore the solution is (6,-4)</h3>

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3 years ago

Does the relation s={(5.2). (3.2), (4,2)? state the domain and range

pishuonlain [190]

Domain{5,3,4}
Range{2)

5 0

3 years ago

An oak tree is planted when it is 650 centimeters tall. What is this height in meters?

Mashutka [201]

Answer:

It is 6.5 meters

The centimeter practical unit of length for many everyday measurements. A centimeter is equal to 0.01(or 1E-2) meter.

7 0

3 years ago

Henry wants some of his

Morgarella [4.7K]

Answer:

maybe 14 or 15 im not good with this stuff im in 8th grade and im very very behind a lot im prob gonna delete this app cuz I dont understand anything

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3 years ago

What value of b will cause the system to have an infinite number of solutions?

irga5000 [103]

b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

$\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}$

Let us bring the equations in same form for sake of simplicity in comparison

$\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}$

Now we have two equations

$\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}$

Let us first see what is requirement for system of equations have an infinite number of solutions

If $a_{1} x+b_{1} y+c_{1}=0$ and $a_{2} x+b_{2} y+c_{2}=0$ are two equation

$\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$ then the given system of equation has no infinitely many solutions.

In our case,

$\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}$

As for infinitely many solutions $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$

$\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}$

Hence b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

8 0

3 years ago