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3 years ago

Which value is a solution of the inequality 9 >_ 1/2x

Mathematics

1 answer:

MrRa [10]3 years ago

5 0

Answer:

x $\leq$ 18.

Step-by-step explanation:

Since we have the following inequality, 9 $\geq$ 0.5x, we can multiply both sides of the inequality by 2. Doing this, gets up x $\leq$ 18.

Hope this helped!

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What is the length of segment BC?

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Answer:

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2 years ago

Which shows the dimensions of two rectangular prisms that have volumes of 240 ft3 but different surface areas?

bulgar [2K]

Calculate the volume and surface areas of both rectangular prisms for each option.

A:

Rectangular Prism #1
$\sf V=lwh$
$\sf V=(8)(5)(6)=240~ft^3$

$\sf A=2((8)(5)+(6)(5)+(6)(8))$
$\sf A=236~ft^2$

Rectangular Prism #2
$\sf V=lwh$
$\sf V=(5)(6)(8)=240~ft^3$

$\sf A=2((5)(6)+(8)(6)+(8)(5))$
$\sf A=236~ft^2$

This is incorrect, they have the same volume of 240 cubic feet and the same surface areas.

B:

Rectangular Prism #1
$\sf V=lwh$
$\sf V=(8)(5)(6)=240~ft^3$

$\sf A=2(wl+hl+hw)$
$\sf A=2((8)(5)+(6)(5)+(6)(8))$
$\sf A=236~ft^2$

Rectangular Prism #2
$\sf V=lwh$
$\sf V=(10)(8)(3)=240~ft^3$

$\sf A=2(wl+hl+hw)$
$\sf A=2((10)(8)+(3)(8)+(3)(10))$
$\sf A=268~ft^2$

$\boxed{\sf Correct~Answer}$ : Both have the same volume of 240 cubic feet, but different surface areas.

C:

Rectangular Prism #1
$\sf V=lwh$
$\sf V=(15)(8)(2)=240~ft^3$

$\sf A=2(wl+hl+hw)$
$\sf A=2((15)(8)+(2)(8)+(2)(15))$
$\sf A=332~ft^2$

Rectangular Prism #2
$\sf V=lwh$
$\sf V=(6)(4)(15)=360~ft^3$

$\sf A=2(wl+hl+hw)$
$\sf A=2((6)(4)+(15)(4)+(15)(6))$
$\sf A=348~ft^2$

This is incorrect, they have different surface areas, but only Rectangle #1 has a volume of 240 cubic feet.

D:

Rectangular Prism #1
$\sf V=lwh$
$\sf V=(12)(6)(5)=360~ft^3$

$\sf A=2(wl+hl+hw)$
$\sf A=2((12)(6)+(5)(6)+(5)(12))$
$\sf A=324~ft^2$

Rectangular Prism #2
$\sf V=lwh$
$\sf V=(8)(10)(3)=240~ft^3$

$\sf A=2(wl+hl+hw)$
$\sf A=2((8)(10)+(3)(10)+(3)(8))$
$\sf A=268~ft^2$

This is incorrect, they both have different surface areas but only Rectangle #2 has a volume of 240 cubic feet.

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