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Naddik [55]
3 years ago
12

What is the number of electrons shared in the multiple carbon-carbon bond in one molecule of 1-pentyne?

Chemistry
1 answer:
jeka57 [31]3 years ago
8 0
Where the options are?
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For the reaction 2 Cr(s) + 3 Pb²⁺(aq) ⟶ 3 Pb(s) + 2 Cr³⁺(aq), what is the value of n in the Nernst equation?
Blizzard [7]

Answer:

x

Explanation:

xx

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3 years ago
How would a geologist use absolute dating to determine the age of sedimentary layer?
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Answer:

They can be dated using radioactive carbon. But for rocks older than 50 thousand years they look for layers of igneous rock or volcanic ash above and Bellow the layer of rock/fossil.

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3 years ago
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The oxygen atom of a ketone (such as cyclohexanone) contains 2 lone pairs of electrons. These pairs of electrons most likely res
skelet666 [1.2K]

Answer: The given pairs of electrons most likely reside in sp^{2} type of orbital.

Explanation:

As it is given that two lone pair of electrons are present on the oxygen atom of ketone (such as cyclohexanone).

Also, there will be one bond pair between carbon and oxygen atom.

Hence, total electrons present in the domain are as follows.

2 lone pairs + 1 bon pair of electron = 3 electron domains

This means that there will be sp^{2} type of orbital present.

Thus, we can conclude that given pairs of electrons most likely reside in sp^{2} type of orbital.

5 0
3 years ago
Please help answer this 6 min left in class
vova2212 [387]

Answer:

not sure but i think is B

Explanation:

hope this help.

6 0
3 years ago
A sample of a gas in a balloon has a volume of 2.22 L and temperature of 23.9 °C. Calculate the volume when the temperature is r
nignag [31]

Answer:

Volume = 4.28L

Explanation:

Charles's gas law relates the volume and temperature of a gas at constant pressure. This law says that at constant pressures if we raise the temperature of a gas it will expand and if we reduce the temperature the volume will decrease. The formula is as follows:

{\displaystyle {\frac {V_{1}}{T_{1}}}={\frac {V_{2}}{T_{2}}}}

So, the initial conditions are 2.22L and 23.9 °C ant the final conditions are 46.1 °C we replace them in the equation. And then we solve it.

{\displaystyle {\frac {2.22}{23.9}}={\frac {V_{2}}{46.1}}

{\displaystyle {\frac {2.22}{23.9}} {46.1}={V_{2}

{\displaystyle {4.28}={V_{2}

4 0
3 years ago
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