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laila [671]
4 years ago
6

How would a geologist use absolute dating to determine the age of sedimentary layer?

Chemistry
2 answers:
Sati [7]4 years ago
6 0

Answer:

They can be dated using radioactive carbon. But for rocks older than 50 thousand years they look for layers of igneous rock or volcanic ash above and Bellow the layer of rock/fossil.

Zinaida [17]4 years ago
6 0

Answer:

By dating the age of instrusions and extrusions near a sedimentary rock layer

Explanation:

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A balloon contains 11.1 g of nitrogen monoxide gas (NO). how many molecules are in the balloon?
grandymaker [24]

The number of molecules that are in balloon are = 2.227 x10^23 molecules

<h3> calculation</h3>

calculate the number of moles of NO

moles = mass/molar mass

molar mass  of NO = 14+ 16 = 30 g/mol

moles is therefore=  11.1 g/30g/mol= 0.37 moles

by use of Avogadro's constant that is

                                     1 mole= 6.02 x10^23  molecules

                                          0.37 =? molecules

=(6.02 x10^23 x  0.37 moles)/ 1mole=2.227 x10^23 molecules

4 0
4 years ago
How could you separate a mixture of sulfur, gold and ethanol? <br>​
stira [4]

Answer: Dissolve it  

Explanation:

3 0
3 years ago
Read 2 more answers
Which of the following substances can be used to neutralize HF?
Artemon [7]

Answer:

option (D) NaOH is right answer

4 0
3 years ago
How many moles of solute are present in 150mL of 0.30 mol/L NaOH solution
Sati [7]

Answer: n= 0.045 mol

Explanation: amount of substance in moles is n= cV= 0.30 mol/l· 0.150 l

6 0
3 years ago
Calculate OH- given H3 O+ = 1.40 *10^-4 M
vova2212 [387]

3.16 X 10^-11 M is the [OH-] concentration when H3O+ = 1.40 *10^-4 M.

Explanation:

data given:

H30+= 1.40 X 10^-4 M\

Henderson Hasslebalch equation to calculate pH=

pH = -log10(H30+)

putting the values in the equation:

pH = -log 10(1.40 X 10^-4 M)

pH = 3.85

pH + pOH =14

pOH = 14 - 3.85

pOH = 10.15

The OH- concentration from the pOH by the equation:

pOH = -log10[OH-]

10.5= -log10[OH-]

[OH-] = 10^-10.5

[OH-]  = 3.16 X 10^-11 is the concentration of OH ions when hydronium ion concentration is 1.40 *10^-4 M.

8 0
3 years ago
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