Answer:
carnivores organism get their energy from eating other organisms..
Answer:
1) 1.808 *10^8 vacancies per cm^3
2) 101,64ºC
Explanation:
You can use the following equation relating the number of vacancies with the energy required to produce them and the temperature:
Where N is the number atoms per unit of volume, you can calculate this number with the density of copper:
And you can substitute all values in the equation:
Now you solve for temperature and and use n as 1000 times the value of before:
Answer:
342.3 g
Explanation:
From the question given above, the following data were obtained:
C = 12.011 g/mol
H = 1.00794 g/mol
O = 15.9994 g/mol
Molar mass of C₁₂H₂₂O₁₁ =?
C = 12 × 12.011 = 144.132 g
H = 22 × 1.00794 = 22.17468 g
O = 11 × 15.9994 = 175.9934 g
Total mass = 144.132 + 22.17468 + 175.9934
Total mass = 342.3 g
Answer:
6.4×10¯³ g of O₂.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CH₄ + 2O₂ —> CO₂ + 2H₂O
Next, we shall determine the masses of CH₄ and O₂ that reacted from the balanced equation. This can be obtained as follow:
Molar mass of CH₄ = 12 + (4×1)
= 12 + 4
= 16 g/mol
Mass of CH₄ from the balanced equation = 1 × 16 = 16 g
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ from the balanced equation = 2 × 32 = 64 g
SUMMARY:
From the balanced equation above,
16 g of CH₄ reacted with 64 g of O₂.
Finally, we shall determine the mass of O₂ needed to react with 1.6×10¯³ g of CH₄. This can be obtained as illustrated below:
From the balanced equation above,
16 g of CH₄ reacted with 64 g of O₂.
Therefore, 1.6×10¯³ g of CH₄ will react with = (1.6×10¯³ × 64) / 16 = 6.4×10¯³ g of O₂
Thus, 6.4×10¯³ g of O₂ is needed for the reaction.
