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Alex_Xolod [135]
2 years ago
5

Why do non-metal aroms form covalent bonds e.g. H2O​

Chemistry
1 answer:
Oksana_A [137]2 years ago
7 0

Answer:

Covalent bonds usually occur between nonmetals. For example, in water (H2O) each hydrogen (H) and oxygen (O) share a pair of electrons to make a molecule of two hydrogen atoms single bonded to a single oxygen atom. ... Covalent compounds tend to be soft, and have relatively low melting and boiling points.

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MissTica

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100,284,896

Explanation:

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3 years ago
The fundamental sedimentary rock unit is called<br> a. layer formation group bed
Evgesh-ka [11]
<h3><u>Answer;</u></h3>

Formation

<h3><u>Explanation;</u></h3>
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Read 2 more answers
HELP ME PLZ!!!!
Degger [83]
The answers is B that’s your answer
4 0
2 years ago
Which substance would have the highest melting point, based on electronegativity?
kenny6666 [7]

Water, H₂O, will have the highest melting point.

Explanation:

So here we have listed the hydrides of oxygen, sulphur, selenium and tellurium.

From this elements oxygen have the highest electronegativity and as a consequence the oxigen hydride (water, hydrogen dioxide) it is able to form hydrogen bonds between molecules. So you need more energy to overcome the interactions between molecules in water that for the other compounds.

Water, H₂O, will have the highest melting point between the listed hydrides.

Learn more about:

hydrogen bonds

brainly.com/question/3157382

#learnwithBrainly

4 0
3 years ago
The number of grams of H2 in 1470 mL of H2 gas. ​
Lorico [155]

Answer:

0.1313 g.

Explanation:

  • It is known that at STP, 1.0 mole of ideal gas occupies 22.4 L.
  • Suppose that hydrogen behaves ideally and at STP conditions.

<u><em>Using cross multiplication:</em></u>

1.0 mol of hydrogen occupies → 22.4 L.

??? mol of hydrogen occupies → 1.47 L.

∴ The no. of moles of hydrogen that occupies 1.47 L = (1.0 mol)(1.47 L)/(22.4 L) = 6.563 x 10⁻² mol.

  • Now, we can get the no. of grams of hydrogen in 6.563 x 10⁻² mol:

<em>The no. of grams of hydrogen = no. of hydrogen moles x molar mass of hydrogen</em> = (6.563 x 10⁻² mol)(2.0 g/mol) = <em>0.1313 g.</em>

5 0
2 years ago
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