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amm1812
3 years ago
9

5) A scientist adds 1.2 liters of water to a 5.0 liter solution, causing the molarity to become 0.4 M. What was the molarity of

the initial solution before the dilution? ​
Chemistry
1 answer:
ivanzaharov [21]3 years ago
5 0

Explanation:

i hope i helped you in this problem

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Select the TRUE statements below regarding the coordination compound prepared in lab. Group of answer choices The coordination c
Vanyuwa [196]

Answer: Hello the compound is missing but I was able to get the Full question and missing compound . ( compound = copper sulfate )

<em>answer</em> : statement ; 2 , 3 and 5

Explanation:

The true statements regarding the coordination compound ( copper sulfate ) are :

  • The ligand must have at least one unshared pair of valence electrons in order to covalently bond with transition metal in the coordination compound ( statement 2 )
  • Ethanol was used during crystallization of the coordination compound because the compound is soluble in ethanol ( statement 3 )
  • The colors of many coordination compounds are the result of light absorption by the d electrons on the transition metal ( statement 5 )

During the coordination of compounds dative bonds exits between the transition metals and the Ligands molecules

7 0
3 years ago
Can the crabs see the plankton they eat near the ocean floor?
cricket20 [7]

Answer:

Explanation:

The crabs cannot see the plankton they eat near the ocean floor. For the crabs to see the plankton, some color of visible light would need to reach the plankton so that it can be reflected into the crabs' eyes.

4 0
3 years ago
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Can someone please check k these to see if I have any mistakes
iren [92.7K]
I do not see any mistakes so I think you’re good!
4 0
3 years ago
202H8(9) + 7 O2(g) &gt; 4CO2(g) + 6 H2O(9).
lilavasa [31]

since the concentration of Carbon Dioxide will increase, it would make Q > K, cause equilibrium to shift in the direction with less moles of gas to alleviate the extra pressure. In this case, the reaction will shift left because there are fewer moles of gas present.

4 0
2 years ago
Find the empirical formula of the compound ribose, a simple sugar often used as a nutritional supplement. A 14.229 g sample of r
MakcuM [25]

Answer:

CH2O

Explanation:

Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.

C = 5.692/14.229 * 100 = 40%

O = 7.582/14.229 * 100 = 53.29%

H = 0.955/14.229 * 100 = 6.71%

We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.

C = 40/12 = 3.333

O = 53.29/16 = 3.33

H = 6.71/2 = 6.71

Dividing by the smaller value which is 3.33

C = 3.33/3.33 = 1

O = 3.33/3.33= 1

H = 6.71/3.33 = 2

The empirical formula of the compound ribose is CH2O

6 0
3 years ago
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