Answer : Given data ;
Δ G° = 212 KJ/molTemperature is = 25+273 = 298 KAnd gas constant R = 0.008314 KJ/mol
The reaction is NiO(s) ⇌ Ni(s) +

We can find out the pressure on oxygen by using the equation of gibb's free energy with remainder quotient which is, ΔG = ΔG° +RT lnQ
when at equilibrium Q = K, here K is equilibrim constant, and ΔG becomes 0;
so we get, 0 = ΔG° + RT ln K
on rearranging we get, ln K = ΔG° / (RT)
ln K = 212 / (0.00831 X 298) = 85.6
Here, now K = = 1.51 X

When we get K = 1.51 X

But, K =

So, (1.51 X

)

= 3.87 X

Hence, the
pressure of oxygen will be = 3.87 X
Pa
Now, Pa to atm conversion will be 3.756 X
atm
Answer: A
Explanation:
Please check the attachment for the answer.
Answer:
3.98 g
Explanation:
Step 1. Write the balanced chemical reaction. In this case, magnesium reacts with oxygen to produce magnesium oxide:

\\
Step 2. Calculate the number of moles of magnesium:

\\
Step 3. Calculate the number of moles of oxygen:

\\
Step 4. Identify the limiting reactant comparing the equivalents. Equivalent of Mg:

Equivalent of oxygen:

Therefore, Mg is the limiting reactant.
\\
Step 5. According to the stoichiometry of this reaction:

\\
Step 6. Convert the number of moles of MgO into mass:

is 7 cus the valance electron for sodium is Ne 3s1 and for chlorine is Ne 3s13p5