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Feliz [49]
3 years ago
6

A long time ago Dulani found an island shaped like a triangle with three straight shores of length 3 km 4 km and 5 km.He said no

body could come within 1km of his shore. What was the area of his exclusion zone?

Mathematics
1 answer:
VikaD [51]3 years ago
5 0
To find the area of his exclusion zone you would need to understand that a triangle with dimensions of 3, 4, and 5 represent a right triangle.

This means the exclusion zone would be applied to the base and the height of the triangular space.

You would add 2 km to the 3 km, and 2 km to the 4 km to create a new height of 5 km and a new base of 6 km.

Please see the attached picture to understand this.

You will find the area of the total space created by the new triangle and subtract the space represented by the original triangle to find the area of the exclusion zone.

(1/2 x 6 x 5) - (1/2 x 4 x 3)
15 km² -6 km² equals 9 km².

The exclusion space is 9 km².

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4 0
2 years ago
(4x + 4)(ax – 1) – x2 +4
Oksana_A [137]

Answer:

b=-3

Step-by-step explanation:

If the expression simplifies to bx that means the x^{2} terms and the constant terms must be cancel out.

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(4x+4)(ax-1)-x^{2} +4\\=(4ax^{2} -4x+4ax-4)-x^{2} +4\\=4ax^{2} -x^{2} -4x+4ax-4+4\\=4ax^{2} -x^{2} -4x+4ax

We know –4 + 4 will cancel out. If we simplify this expression to only an x term, then the x^{2} terms should be cancelled. Therefore, we say that 4ax^2 – x^2 = 0.

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If we put a = ¼, then we can find the value of b:

=4(\frac{1}{4} )x^{2} -x^{2} -4x+4(\frac{1}{4} )x\\=x^{2} -x^{2} -4x+x\\ (cancel out x^{2} terms)\\

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Therefore, b = –3.

8 0
3 years ago
If you disssolved 50 g of sugar in 30 g of water what would the sugar concentration be
Lelu [443]
<h3>Answer:  62.5%</h3>

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The percentage of sugar is 50/80 = 5/8 = 0.625 = 62.5%

5 0
2 years ago
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