Answer:
It would be between -3 and 2
Step-by-step explanation:
cause -2.5 is greater than -3 and its less than 2
Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.
We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.
The Law of Cosines features the 3 side lengths of a triangle, plus the measure of the angle opposite one of those sides.
We want angle x, which is opposite the side of length 39.
Then: a^2 = b^2 - 2ab cos C becomes 39^2 = 36^2 + 59^2 - 2(36)(59)cos x
or 1521 = 3481 + 1296 - 2(36)(59) cos x
Subtract (3481+1296) from both sides: 1521 - 4777 = -4248cos x
-3256 = -4248cos x
-3256
Then: cosx = --------------- = 0.766
-4248
Solving for x: x = arccos -0.766 = 0.698 radian, or 40 degrees (answer)
Answer:
1. 9/10
2. 15/16
4. 3/5
5. 3/5
Step-by-step explanation:
1. 7/10 + 2/10 = 9/10
2. 13/16 + 2/16 = 15/16
4. 7/15 + 2/15 = 9/15 = 3/5
5. 9/20 + 3/20 = 12/20 = 3/5
3(2)+2(3)=12 <<<< is the answer! :)