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Sladkaya [172]
3 years ago
11

5b +20y A. 5(b+4y) B. 5(4y+b) C. 2(b+10y)

Mathematics
2 answers:
enot [183]3 years ago
6 0

Answer:

a once again it is easy the answer is A

Step-by-step explanation:

Andru [333]3 years ago
6 0
The answer is A because 5 times b is 5B and 5 times 4y is 20y so 5B+20y
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You are a host at a restaurant. You make $7.75 per hour. You work 17 hours each week and are paid biweekly. How much is your pay
Elodia [21]

Answer:

$263.50

Step-by-step explanation:

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5 0
3 years ago
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Please help!! x = 2 - 3 cos t, y = 1 + 4 sin t in rectangular form?<br><br> thank you! :)
sukhopar [10]

Answer:

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

Step-by-step explanation:

x=2-3\cos(t)

y=1+4\sin(t)

Let's solve for \cos(t) in the first equation and then solve for \sin(t) in the second equation.

I will then use the following identity to get right of the parameter, t:

\cos^2(t)+\sin^2(t)=1 (Pythagorean Identity).

Let's begin with x=2-3\cos(t).

Subtract 2 on both sides:

x-2=-3\cos(t)

Divide both sides by -3:

\frac{x-2}{-3}=\cos(t)

Now time for the second equation, y=1+4\sin(t).

Subtract 1 on both sides:

y-1=4\sin(t)

Divide both sides by 4:

\frac{y-1}{4}=\sin(t)

Now let's plug it into our Pythagorean Identity:

\cos^2(t)+\sin^2(t)=1

\frac{x-2}{-3})^2+(\frac{y-1}{4})^2=1

\frac{(x-2)^2}{(-3)^2}+\frac{(y-1)^2}{4^2}=1

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

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Answer:

1.33333333333

Step-by-step explanation:

There is your answer!

3 0
3 years ago
What is the value of 4(25-5)?
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First you subtract 25 from 5 which equals 20 then you multipliy 4 to 20 and you get 80...so 80 is your solution.
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3 years ago
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