4 years ago

67a(t+z)=45z+67 solve for (z)

Mathematics

1 answer:

lora16 [44]4 years ago

3 0

Answer: z = $\frac{67(1 - at)}{67a - 45}$

Step-by-step explanation:

67a(t + z) = 45z + 67

67at + 67az = 45z + 67

-67at -45z -45z -67at

67az - 45z = 67 - 67at

z(67a - 45) = 67 - 67at

÷ (67a - 45) ÷ (67a - 45)

z = $\frac{67 - 67at}{67a - 45}$

= $\frac{67(1 - at)}{67a - 45}$

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