The answer is <span>D: its acceleration is 1.25 meters/second^2.</span>
The solution for this is:
Power = Energy transferred / Time taken
Energy Transferred in one second ( Power) = mgh/s
= (1.2x10^6)(9.8)(50) = 588000000 J/s
Power = 588000000 W
Or
Power is work done / time
Work done in one second = [ rate of fall of mass]
gh = 1.2* *9.81*50 x 10^6 J/s
= 5.886e+8 W
The wavelength of the interfering waves is 3.14 m.
<h3>Calculation:</h3>
The general equation of a standing wave is given by:
y = 2A sin (kx) cos (ωt) ......(1)
The given equation represents the standing wave produced by the interference of two harmonic waves:
y = 3 sin (2x) cos 5t .......(2)
Comparing equations (1) and (2):
k = 2
We know that,
k = 2π/λ
λ = 2π/k
λ = 2 (3.14)/ 2
λ = 3.14 m
Therefore, the wavelength of the interfering waves is 3.14 m.
I understand the question you are looking for is this:
Two harmonic waves traveling in opposite directions interfere to produce a standing wave described by y = 3 sin (2x) cos 5t where x is in m and t is in s. What is the wavelength of the interfering waves?
Learn more about interfering waves here:
brainly.com/question/2910205
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He should confront her about it and if after that point she continues report it to the chess team
Answer:
We cannot place three forces of 5g, 6g, and 12g in equilibrium.
Explanation:
Equilibrium means their sum must be zero.
Here the forces are 5g, 6g, and 12g.
For number of forces to be in equilibrium the magnitude of largest vector should be less than sum of the magnitude of other vectors.
Here
Magnitude of largest force = 12 g
Sum of magnitudes of other forces = 5g + 6g = 11g
Magnitude of largest force > Sum of magnitudes of other forces
So this forces cannot form equilibrium.
We cannot place three forces of 5g, 6g, and 12g in equilibrium.
