Why is there convection in the outer core and what is the result of this?
1 answer:
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Assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².
Missing part of the question: determine the magnitude of Porsha's acceleration.
Given the data in the question;
- Mass of Porsha;
- Mass of Zorn;
- Force of Porsha push;
Magnitude of Porsha's acceleration;
To determine the magnitude of Porsha's acceleration, we use Newton's second laws of motion:
Where m is the mass of the object and a is the acceleration.
We substitute the mass of Porsha and the force he used into the equation
Therefore, assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².
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Answer:
Final temperature, T2 = 314.9 Kelvin
Explanation:
Given the following data:
Mass = 0.9kg
Initial temperature, T1 = 10°C to Kelvin = 10 + 273 = 283K
Quantity of heat = 120,000 J
Specific heat capacity = 4182 j/kgK
To find the final temperature;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
Making dt the subject of formula, we have;
Substituting into the equation, we have;
dt = 31.9K
Now, the final temperature T2 is;
But, dt = T2 - T1
T2 = dt + T1
T2 = 31.9 + 283
T2 = 314.9 Kelvin