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Andreas93 [3]
3 years ago
10

What is KBr (periodic table) def

Physics
1 answer:
adelina 88 [10]3 years ago
5 0

Answer: Answered already

Explanation:

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How do inertia and centripetal force combine to keep an object moving in circular motion?
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<span>Centripetal force acts toward the center of the circle, and inertia keeps the object moving forward.
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An object in circular motion has velocity that is constantly changing. The direction of the acceleration is
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<h2>Answer: Toward the center of the circle.</h2>

This situation is characteristic of the uniform circular motion , in which the movement of a body describes a circumference of a given radius with constant speed.  

However, in this movement the velocity has a constant magnitude, but its direction varies continuously.

Let's say \vec{V} is the velocity vector, whose direction is perpendicular to the radius r of the trajectory, therefore   the acceleration \vec{a} is directed toward the center of the circumference.

 

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3 years ago
Imagine that Earth stops orbiting the Sun but continues to rotate in place about its own axis at its current rate. In this case,
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Answer:

The length of the solar day will get shorter.

Explanation:

  • The blue planet Earth not only rotates around it's own axis but also rotates around the Sun and everyday it moves a little bit around the axis.
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3 years ago
A biker pedals hard for 3 seconds. What is his initial velocity if he accelerated by 4m/s2 until he's going 20m/s. (Which equati
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answer is option 4

Explanation:

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4 0
3 years ago
A 1000 kg car moving a 10 m/s collides with a stationary 2000 kg truck. The two vehicles interlock as a result of the collision.
IgorLugansk [536]

Answer:

v₃ = 3.33 [m/s]

Explanation:

This problem can be easily solved using the principle of linear momentum conservation. Which tells us that momentum is preserved before and after the collision.

In this way, we can propose the following equation in which everything that happens before the collision will be located to the left of the equal sign and on the right the moment after the collision.

(m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}

where:

m₁ = mass of the car = 1000 [kg]

v₁ = velocity of the car = 10 [m/s]

m₂ = mass of the truck = 2000 [kg]

v₂ = velocity of the truck = 0 (stationary)

v₃ = velocity of the two vehicles after the collision [m/s].

Now replacing:

(1000*10)+(2000*0)=(1000+2000)*v_{3}\\v_{3}=3.33[m/s]

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