3 years ago

How to solve this equation

Mathematics

1 answer:

aniked [119]3 years ago

3 0

What the equation?????

You might be interested in

Two angles are complementary. The measurement of ∠GHI is (5x+6)∘ and ∠JKL measures (3x+4)∘. What are the measures of the two ang

Alex777 [14]

Answer:

Angle GHI measures 56º, and angle JKL measures 34º.

Step-by-step explanation:

Complementary Angles:

If two angles are complementary, the sum of their measures is 90º.

∠GHI is (5x+6)∘ and ∠JKL measures (3x+4)∘.

Since they are complementary:

$5x + 6 + 3x + 4 = 90$

$8x + 10 = 90$

$8x = 90 - 10$

$8x = 80$

$x = \frac{80}{8}$

$x = 10$

Measures:

GHI: 5*10 + 6 = 50 + 6 = 56º

JKL: 3*10 + 4 = 30 + 4 = 34º.

Angle GHI measures 56º, and angle JKL measures 34º.

5 0

3 years ago

What is the sign of the product? Help plz

klio [65]

A positive
as there are 4 negetive multiplied

6 0

3 years ago

Steven put together 981 pieces of a puzzle. About how many pieces did he put together? Round to the nearest thousand. Use what y

Colt1911 [192]

About 1,000 puzzle pieces

3 0

2 years ago

1. There are 78 sophomores at a school. Each is required to take at least one year of either chemistry or physics, but they may

SVETLANKA909090 [29]

We are given that there are a total of 78 students. If we set the following variables:

$\begin{gathered} C=\text{students only in chemestry} \\ P=\text{students only in physics} \\ PC=\text{students in physics and chemistry} \end{gathered}$

Then, the sum of all of these must be 78, that is:

$C+P+PC=78$

Since there are 15 in chemistry and physics and 47 in chemistry, we may replace that into the equation and we get:

$47+P+15=78$

Simplifying:

$62+P=78$

Now we solve for P by subtracting 62 on both sides:

$\begin{gathered} 62-62+P=78-62 \\ P=16 \end{gathered}$

Therefore, there are 16 students in physics

3 0

1 year ago

50 points hdhfskjdhsddjjdhj

NikAS [45]

Thank you very much UwU

8 0

3 years ago

Read 2 more answers