An electron moving through an electric field experiences an acceleration of 5800 × 103 m/s 2 . Find the magnitude of the electri
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Answer:
-2π ≤ ∅ ≤ 3π/2
0 ≤ ∅ ≤ π/2
Explanation:
In simple harmonic motion, the displacement and velocity vectors are as follows:
where ∅ is the phase angle. At t = 0, the initial displacement and velocity are
According to two equations, we need to find the ∅ values which makes both cosine and sine terms positive.
So, ∅ is in the range: [-2π, -3π/2] and [0,π/2]