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earnstyle [38]
3 years ago
9

1) if you could eliminate one item from your diet to improve your heath, what would it be?

Physics
2 answers:
const2013 [10]3 years ago
5 0

Answer:

1. I would eliminate chocolate. I normally eat healthy but when chocolate's around, I can't resist it though, it has a naturally bad affect on my health. Chocolate makes me nauseas but I still eat it because the taste is unbearable.

2. I would add fish. I hear that it's a good protein, and I don't eat chicken or meat or fish at all because of the texture, vegan or vegetarian? Eh, no. But, I would add fish because many people say it has great health benefits.

Makovka662 [10]3 years ago
3 0

Answer:

Rice

Explanation:

Because I can't control eating lots of rice

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Explanation:

The following data were obtained from the question:

Mass of water (Mw) = 0.5 Kg

Specific heat capacity of water (Cw) = 4.18 KJ/Kg°C

Initial temperature of water (Tw1) =

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Change in temperature (ΔT) = T2 – Tw1 = T2 – 22°C

Mass of copper (Mc) = 0.5 Kg

Specific heat capacity of copper (Cc) = 0.386 KJ/kg°C

Initial temperature of copper (Tc1) = 115°C

Change in temperature (ΔT) = T2 – Tc1 = T2 – 115°C

Final temperature (T2) =..?

Note: Both the water and the piece copper will have the same final temperature and the heat will be zero since the water will cool the piece of copper.

Thus, we can determine the final temperature of the water and copper as follow:

Q = MwCwΔT + McCcΔT

0 = 0.5 x 4.18 x (T2 – 22) + 0.5 x 0.386 x (T2 – 115)

0 = 2.09 (T2 – 22) + 0.193 (T2 – 115)

0 = 2.09T2 – 45.98 + 0.193T2 – 22.195

Collect like terms

2.09T2 + 0.193T2 = 45.98 + 22.195

2.283T2 = 68.175

Divide both side by the coefficient of T2 i.e 2.283

T2 = 68.175/2.283

T2 = 29.8 ≈ 30°C

Therefore, the final temperature of water and copper is 30°C.

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