Answer:
Explanation:
Assuming the following question: A force F = (cx 3.00x2 li acts on a particle as the particle moves along an x axis, with F in newtons, x in meters, and c a constant. At x = 0 m, the particle's kinetic energy is 22.0 J; at x = 4.00 m, it is 9.00 J. Find C.
Solution to the problem
We know that the work for this case since we don't have change of potential energy is given by:
Where KE means kinetic energy
And we know that the work can be expressed like this:
If we integrate the left part we got:
about 1/10th as great by bending your legs
Time extended decreases acceleration value.
solve using Newton's 2nd and Uniform Acceleration Laws. plug in values for descending.
Vf = 0.0 m/s
Vi = 10 m/s
t = 1 s
Acceleration is given by
a = [Vf - Vi] / t
a = [ (0.0 m/s) - (10 m/s) ] / (1 s)
a = [ -10 m/s ] / (1 s)
a = -10 m/s^2
Solve the same thing, but with time 10x, so t = 10 s
a = [ (0.0 m/s) - (10 m/s) ] / (10 s)
a = [ -10 m/s ] / (10 s)
a = -1 m/s^2
Solve for first force and second force, using a mass of 100 kg
F = m * a
F = (100 kg) * (-10 m/s^2)
F = -1,000 N
F = (100 kg) * (-1 m/s^2)
F = -100 N
So divide long-force by short-force
(-100 N) / (-1,000 N) = 0.1 (which is 1/10)
Answer:
the two balls will hit the ground at the same time.
Explanation:
The time of dropping, in the following equation, is related to both the distance travel s and the gravitational acceleration g, which are the same for both ball (if we neglect air resistance), no matter what their mass are.
So the time it takes to drop 2 balls are the same. They will hit the ground at the same time.
The atomic number is the number of protons in the nucleus of an atom. The number of protons define the identity of an element (i.e., an element with 6 protons is a carbon
So I believe it’s 6 hope this helps if not reply back
