Answer:
From the level of high tide to low tide, it's 18 feet.
Step-by-step explanation:
To find the change in water level, we multiply the rate (3 ft / hr) by the time (6 hrs), obtaining 18 ft.
The water level changes by 18 ft.
Step-by-step explanation:
tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)
= (sin2B + cos2B)/[(cosB)(sinB)]
= 1/[(cosB)(sinB)]
= (1/cosB)(1/sinB)
= (secB)(cscB)
Answer:
EH = 3.31
Step-by-step explanation:
We have been given a right angle triangle EKL. As KH has been given as the altitude (perpendicular) of the right angled triangle, and K is the right angle, we can say that EK is tthe base of the triangle and EH is the only side lleft, which is the hypotenuse of the triangle.
Where,
EK = Base = 3
KH = perpendicular altitude
EH = Hypotenuse
m<K = 90
m<E = 25
We know that
cosθ = Base/ Hypotenuse
cos 25 = 3/ EH
EH = 3/cos25
EH = 3.31
Perpendicular alitutude can also be calculated by using the formula for tanθ.
7 times 30 is 210
answer: 30
Is the second paragraph meant to throw you off??? Because the answer to the question does not rely on the information based from the second paragraph...
Anyway, we know that the turtle started from (0, 0) and moved to (10, 8). Let's assume that (0, 0) is (x1, y1), and that (10, 8) is (x2, y2) for the sake of calculations.
To find how far the turtle moved to the right (along the x-axis) we take x1 from x2:
x2 - x1 = 10 - 0
= 10 = x2
***this is the "run"
To find how far the turtle moved upwards (along the y-axis) we take y1 from y2:
y2 - y1 = 8 - 0
= 8 = y2
***this is the "rise"
Notice that when something moves away from the origin the distance it traveled along the x-axis and y-axis is the same as its final position (or coordinates to where it traveled to).
Therefore, the,
slope = rise / run
= x2 / y2
= 10 / 8
= 5 / 4 (preferable for use)
= 1.25
