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3 years ago

What is Pi? I honestly do not know , I am 10

2 answers:

8 0

Pi is the ratio of a circle's circumference to its diameter, which is roughly equivalent to 3.14 (rounded up).
Hope this helps! :)

choli [55]3 years ago

5 0

Pi is the ratio of a circles circumference to it's diameter.

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Find the equation for a parabola if the vertex is 6,9

devlian [24]

The equation for a parabola with vertex (h, k) and vertical scale factor "a" is
y = a(x -h)² + k

One parabola with vertex (6, 9) is
y = (x-6)² +9

6 0

4 years ago

In the line 3y=4x-1 and 9y=x+3 are parallel to each other the value of q is

jonny [76]

Do you mean the value of y? there is no q in these equations.

5 0

3 years ago

Read 2 more answers

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

Can you answer and explain please

nalin [4]

Answer what exactly?

8 0

3 years ago

Modeling Real Life A person weighs

grin007 [14]

The student weighs 108.8 pounds on saturn. 85x2.34=198.9 -90.1 = 108.8

3 0

3 years ago