Question

The final game is altered:

Answer 1

Answer:

A= 7/13; B=9/14; C= 6/13; D= 63/182; E= 5/14; F= 15/91; G= Red

Step-by-step explanation:

Answer 2

Answer:

$\bf A=\frac{7}{13},B = 9,C=13,D=\frac{63}{182},E=\frac{5}{14},F=\frac{15}{91}\textbf{ and }G=RED$

Step-by-step explanation:

Number of red balls in bag 1 = 5

Number of blue balls in bag 1 = 9

$\text{So, Probability of drawing red ball = }\frac{5}{14}\\\\\text{Probability of drawing blue ball = }\frac{9}{14}$

So, On comparing with the tree diagram :

$B = 9\text{ and }E=\frac{5}{14}$

Number of red balls in bag 2 = 6

Number of blue balls in bag 2 = 7

$\text{So, Probability of drawing red ball = }\frac{6}{13}\\\\\text{Probability of drawing blue ball = }\frac{7}{13}$

$Now, D = \frac{7}{13}\times\frac{9}{14}=\frac{63}{182}$

$And, F = \frac{6}{13}\times\frac{5}{14}=\frac{15}{91}$

$\bf A=\frac{7}{13},B = 9,C=13,D=\frac{63}{182},E=\frac{5}{14},F=\frac{15}{91}\textbf{ and }G=RED$