The percent increase in enrollment is 6 %
The operation used in first step is finding the difference between final value and initial value
<h3><u>Solution:</u></h3>
Given that This year, 1,272 students enrolled in night courses a a local college
Last year only 1,200 students enrolled.
To find: percent increase in the enrollment
The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.
<em><u>The percent increase is given as:</u></em>
Here initial value (last year) = 1200 and final value(this year) = 1272
Substituting the values in above formula,
Thus percent increase is 6 %
9514 1404 393
Answer:
18
Step-by-step explanation:
The least common denominator (LCD) is the least common multiple (LCM) of the denominators.
Here, the denominators are ...
9 = 3·3
6 = 3·2
So, their LCM is 3·3·2 = 18.
The least common denominator of the given fractions is 18.
__
7/9 = 14/18
11/6 = 33/18
Step 1) Divide 6 and 4 (the last 2 numbers) and bring everything else down
<em>6x^24x+2x+4</em>
Step 2) Place in parentheses
<em>(6x^24x)+(2x+4)</em>
Step 3) Figure out what you can take out of each parentheses.
**In the first one, you can take out 6x because both numbers have x and 6 is the largest number 6 and 24 can go into.**
**In the second one, you can only take out 2 because 2 is the largest number that goes into 2 and 4.**
Step 4) You will know you did it correctly when the parentheses match up
<em>6x(x+4) + 2(x+4)</em> <<< this is how it should look
Answer: <em>(6x+2)(x+4)</em>
Answer:
$20 dollars and $10 dollars per hour
Step-by-step explanation:
the line starts at 20 and it escalates by 10 ( 10,20,30,40,50,ect)
i just had a question like this and i'm in middle school, i tried to look for the answer on here but no one answered so when i took time to answer the problem i got it right on the first try.. anyway i hope this helps .!
