Ok let me start it from here.
you are studying about properties of natural numbers or whole number or may be integers.
So , In this Question you have to follow property of addition of integers.
⇒7+3=( You are at the point 7 on the number line or on the tight rope , you are moving (+3) on the right direction.) So you will reach at 7+1+1+1=10
⇒4+2=( You are at the point 4 on the number line or on the tight rope , you are moving (+2) on the right direction.) So you will reach at 4+1+1=6
In first case Cecil has taken total walk of 10 units and in second case Cecil has taken a walk of 10 units.
Answer:
None of the numbers are Perfect Square.
Step-by-step explanation:
6, 10, 12, and 14 are not <u>Perfect Square</u>, because each number are multiplied by two different numbers:
Answer:
Roots are not real
Step-by-step explanation:
To prove : The roots of x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0 are real for all real values of k ?
Solution :
The roots are real when discriminant is greater than equal to zero.
i.e. b^2-4ac\geq 0b
2
−4ac≥0
The quadratic equation x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0
Here, a=1, b=1-k and c=k-3
Substitute the values,
We find the discriminant,
D=(1-k)^2-4(1)(k-3)D=(1−k)
2
−4(1)(k−3)
D=1+k^2-2k-4k+12D=1+k
2
−2k−4k+12
D=k^2-6k+13D=k
2
−6k+13
D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))
For roots to be real, D ≥ 0
But the roots are imaginary therefore the roots of the given equation are not real for any value of k.
A+(-1.3)=-4.5
Add 1.3 to both sides of the equation
a=-3.2
Answer:
4.3
Step-by-step explanation:
