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3 years ago

Elijah bought a rectangular for mat that was 1/2 meter long by 3/10 meter wide.How many square s is the door mat divided into

1 answer:

5 0

We can find the area of the doormat, in square meters, by multiplying 1/2 and 3/10, getting 3/20. Each square is 1/10*1/10=1/100 square meters.

(3/20)/(1/100) will give the ratio of the size of the doormat to the size of the squares, and thus the amount of squares needed. This is equal to 15 squares, so the doormat will be divided into 15 squares.

You might be interested in

5. What is the solution to the equation -2.5(x-4)=-3x+4?

lana66690 [7]

Answer:

x = -12

Step-by-step explanation:

-2.5(x-4)=-3x+4

Distribute

-2.5x +10 = -3x +4

Add 3x to each side

-2.5x+10 +3x = -3x+4+3x

.5x +10 = 4

Subtract 10 from each side

.5x+10-10=4-10

.5x = -6

Divide by .5

.5x/.5 = -6/.5

x = -12

6 0

3 years ago

Read 2 more answers

a line passes through the point (-4 , -5) and has a slope of -5/4. Write an equation in slope - intercept form of this line

IgorLugansk [536]

Answer:

y=-5/4x-10

Step-by-step explanation:

(✿◡‿◡) <-- she wants Brainliest

3 0

3 years ago

A pair of parallel lines is cut by a transversal, as shown:

Hitman42 [59]

The correct answer is option C which is x = y.

<h3>What is the alternate interior angle?</h3>

The angle formed by the line intersecting two parallel lines is called the alternate interior angle. This two angles are equal in magnitude.

In the given figure we can see that the angle x will be equal to the angle y because of the right opposite angles.

Since two parallel lines are cutting the upper part at x so the same lower part will be also x due to corresponding angles.

Now just right opposite to x there is an angle y so the angles x and y will be equal to each other.

Therefore the correct answer is option C which is x = y.

To know more about alternate interior angles follow

brainly.com/question/24839702

#SPJ1

8 0

2 years ago

Karen is starting a career as a professional wildlife photographer and plans to photograph Canadian Geese at one of the staging

balandron [24]

Answer:

$5000*0.816 = $4082

Step-by-step explanation:

It's a strange question, but based on the statement and the question it sounds like it's a poisson distribution:

* For 3 days she was able to get 2 good shots (<em>typical of that time of the year</em>)

* Good shots happen randomly

* Each day is independent of another

Let's call 'p' the probability that she makes a good shot per day

Let's call 'n' the number of days Karen is taking shots.

So, if in 3 days he got 2 good shots and that is typical at that time of the year, then the expected value for the number of good shots (X) is:

$E(x)=\frac{2}{3}$

For a Poisson distribution $E (x)=\lambda\\\lambda= np$

So:

$\lambda =\frac{2}{3}$

For a Poisson distribution the standard deviation is:

$\sigma = \sqrt{\lambda}\\\sigma = \sqrt{\frac{2}{3}}$

$\sigma = 0.816$ this is the standard deviation for the number of buentas taken.

So the standard deviation for income is the price of each shot per sigma

$5000*0.816 = $4082, which is the desired response.

3 0

3 years ago

Determine whether the set of vectors <img src="https://tex.z-dn.net/?f=%20v_%7B1%3D%283%2C2%2C1%29%2C%20v_%7B2%7D%20%3D%28-1%2C-

Korolek [52]

Since each vector is a member of $\mathbb R^3$ , the vectors will span $\mathbb R^3$ if they form a basis for $\mathbb R^3$ , which requires that they be linearly independent of one another.

To show this, you have to establish that the only linear combination of the three vectors $c_1\mathbf v_1+c_2\mathbf v_2+c_3\mathbf v_3$ that gives the zero vector $\mathbf0$ occurs for scalars $c_1=c_2=c_3=0$ .

$c_1\begin{bmatrix}3\\2\\1\end{bmatrix}+c_2\begin{bmatrix}-1\\-2\\-4\end{bmatrix}+c_3\begin{bmatrix}1\\1\\-1\end{bmatrix}=(0,0,0)\iff\begin{bmatrix}3&-1&1\\2&-2&1\\1&-4&-1\end{bmatrix}\begin{bmatrix}c_1\\c_2\\c_3\end{bmatrix}=\begin{bmatrix}0\\0\\0\end{bmatrix}$

Solving this, you'll find that $c_1=c_2=c_3=0$ , so the vectors are indeed linearly independent, thus forming a basis for $\mathbb R^3$ and therefore they must span $\mathbb R^3$ .

4 0

3 years ago