You substitute M for 3 and C for 6. So you get E = (3)(6)(2) which equals 36.
For this case we have the following compound inequality:
11 <7 + 0.25t ≤ 15
We must solve this inequality for time.
We have then:
For 11 <7 + 0.25t:
11 <7 + 0.25t
11 - 7 <0.25t
4 <0.25t
4 / 0.25 <t
16 <t
For 7 + 0.25t ≤ 15:
7 + 0.25t ≤ 15
0.25t ≤ 15 - 7
0.25t ≤ 8
t ≤ 8 / 0.25
t ≤ 32
Therefore, the answer is:
16 <t ≤ 32
Answer:
16 <t ≤ 32
Clara has the desired length in more than 16 weeks, but up to 32 weeks.
Answer:
In A and D the arrows are perpendicular, in B they are parallel and in C they are neither parallel nor perpendicular.
Step-by-step explanation:
Equalities will have the words "is" or "equals" or "the same as" in the wording. These produce a unique solution.
Inequalities have phrases like "at most" or "at least" or "no more than" in them. Solutions are a range of values, ranging between 2 values, or from a particular value to positive or negative infinity.
Answer:
- The system of equations is x + y = 85 and 7/20x+2/5y=31
- To eliminate the x-variable from the equations, you can multiply the equation with the fractions by 20 and multiply the other equation by -7.
- B-She used 60 minutes for calling and 25 minutes for data.
Step-by-step explanation:
It is always a good idea to start by defining variables in such a problem. Here, we can let x represent the number of calling minutes, and y represent the number of data minutes. The the total number of minutes used is ...
x + y = 85
The total of charges is the sum of the products of charge per minute and minutes used:
7/20x + 2/5y = 31.00
We can eliminate the x-variable in these equations by multiplying the first by -7 and the second by 20, then adding the result.
-7(x +y) +20(7/20x +2/5y) = -7(85) +20(31)
-7x -7y +7x +8y = -595 +620 . . . . eliminate parentheses
y = 25 . . . . . . . . simplify
Then the value of x is
x = 85 -y = 85 -25
x = 60
