Always true because addition and subtraction is commutative
-6.2-(-3.96) = -2.24
-3.96-(-6.2)= -2.24
5.71+2.84=8.55
2.84+5.71=8.55
Hope this helped :)
To solve this problem, we make use of the Binomial
Probability equation which is mathematically expressed as:
P = [n! / r! (n – r)!] p^r * q^(n – r)
where,
n = the total number of gadgets = 4
r = number of samples = 1 and 2 (since not more than 2)
p = probability of success of getting a defective gadget
q = probability of failure = 1 – p
Calculating for p:
p = 5 / 15 = 0.33
So,
q = 1 – 0.33 = 0.67
Calculating for P when r = 1:
P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3
P (r = 1) = 0.3970
Calculating for P when r = 2:
P (r = 2) = [4! / 2! 2!] 0.33^2 * 0.67^2
P (r = 2) = 0.2933
Therefore the total probability of not getting more than
2 defective gadgets is:
P = 0.3970 + 0.2933
P = 0.6903
Hence there is a 0.6903 chance or 69.03% probability of
not getting more than 2 defective gadgets.
Answer:
I believe its -36
Step-by-step explanation:
-36+10=-26
-26/2= -13
Answer:
3000
Step-by-step explanation:
Answer:
The pet sitter babysat his dog for 3 hours.
Step-by-step explanation:
You know that a pet sitter charges $ 20 for supplies and $ 10 per hour of service, represented by the equation C = 10*n + 20, which describes the total cost she would charge for n hours of service.
The pet sitter charges a customer $ 50 for his service, so C has a value of $ 50.
Replacing:
50=10*n+20
Solving:
50 - 20= 10*n +20 -20
30= 10*n
30÷10= n
3= n
<u><em>The pet sitter babysat his dog for 3 hours.</em></u>
