First simplify the square roots:
Then simplify the last two terms:
Since 61 is prime, you can't take a rational root out of it.
Answer:
In order to tell if these are congruent triangles we would need to know if angles Y and V were congruent, angles X and W are congruent or if segments XU and WU were congruent.
Step-by-step explanation:
Any of these would work because you can use two different methods to telling that these are congruent triangles.
The first method is called side-angle-side. In it you need two side lengths that are congruent with a congruent angle in the middle. Since we already know that the right angle in the middle is congruent, and we know YU and VU are congruent, we would just need to know the additional side to prove congruence.
The second method is called angle, angle side. In this we need to know that two angles in a row are congruent followed by a side. Since we know the middle angle is the same, knowing either other angles would give us this method as well.
I’d say it’s between B and D
Answer:
ok i rlly dont kno but i do wanna be friends so are you down
Step-by-step explanation:
I'm pretty sure the answer is no. A function looks like this: f(x) = mx + c. Let's add another function, f(y) = ny + d. If the x-intercept is the same, we can subtract c and d from their respective equations. f(x) = mx, f(y) = ny. If the domains are the same, then x and y can have the same value, so we divide it out. f(x) = m, f(y) = n. Finally, if the ranges are the same, the value of f(x) = f(y). So by the substitution property, m=n. Since all the variables equal each other, both functions are equal to f(x) = mx+c! Therefore, they can only be the same function.
Answer: No
