<span>a. True
The question is pretty much the entire definition of a radian. For an unit circle, its entire circumference is 2π and the entire circle has 2π radians. A quarter circle, or 90°, or π/2 radians, have 1/4th of the circumference. And 2π/4 is π/2. This natural relationship is WHY higher mathematics uses radians for the measurement of angles rather than arbitrary units such as degrees.</span>
Both mean and median are measures of the center of a set of data.
Mean is normally preffered to the median except if there is an outlier that has a tendency to affect the mean.
An outlier is a data point that significantly differs from the other data points in a sample.
In the data set above, there is no outlier that will affect the mean.
Therefore, he should use the mean because there are no outliers that affect the mean.
Let us take the second equation first
2a + 2b = 6
Dividing both sides by 2 we get
a + b = 3
a = 3 - b
Putting the value of a in the first equation we get
3a + 4b = 9
3(3 - b) + 4b = 9
9 - 3b + 4b = 9
b = 9 - 9
= 0
Now putting the value of b in the second equation we get
a + b = 3
a + 0 = 3
a = 3
So the value of the unknown variable a is 3 and the value of the unknown variable b is 0.
Answer:
Sum of money invested in corporate bonds = 30,000
Step-by-step explanation:
Total sum = 40,000
The rate of interest for corporate bonds = 10 % = 0.1
The rate of interest for municipal bonds = 6 % = 0.06
Total interest = 3600
Let sum of money invested in corporate bonds = x
The sum of money invested in municipal bonds = 40000 - x
× 0.1 × 1 + (
) × 0.06 × 1 = 3600
(0.1- 0.06) + 2400 = 3600
0.04 = 1200
= 30,000
Since x = sum of money invested in corporate bonds
So sum of money invested in corporate bonds = 30000
Answer:
-4
Step-by-step explanation:
Find the gradient of the line segment between the points (0,2) and (-2,10).
Given data
x1= 0
x2= -2
y1= 2
y2=10
The expression for the gradient is given as
M= y2-y1/x2-x1
substitute
M= 10-2/-2-0
M= 8/-2
m= -4
Hence the gradient is -4
