All categories

3 years ago

Describe the uses of the following safety equipment. Fire extinguisher-

Chemistry

1 answer:

vodka [1.7K]3 years ago

6 0

Answer:

To Put of a Fire.

Explanation:

incase an emergency happens, it's important to have a fir extingushier so the situation doesn't get worse and you can put out any possible fire's.

You might be interested in

Do step 3 as outlined in the lab guide. Record your results in the appropriate blanks.

PolarNik [594]

Explanation:

Do the step 3 as outlined in the lab guide. record your results in the appropriate blank.

8 0

3 years ago

When the temperature of a sample of neon gas increases, what else increases? Distance between the atoms Kinetic energy of the at

Allushta [10]

Answer: Kinetic Energy of the atoms also increases.

Explanation: We are given that the temperature of the gas increases.

Relation between kinetic energy and temperature follows:

$K.E._({avg})=\frac{3RT}{2N_A}$

where, K = Average Kinetic energy

R = Gas constant

T = Temperature

$N_A$ = Avogadro's number

As seen from the relation above, the Kinetic energy of the gas is directly proportional to the temperature, hence as the temperature increases, kinetic energy of the atom also increases.

4 0

3 years ago

Help me with this question please

Natasha_Volkova [10]

Answer:

I dont know sorry i will try my best htough

Explanation:

7 0

2 years ago

What kind of bonds are hydrogen bonds???

34kurt

Hydrogen bonding is a special type of dipole-dipole attraction between molecules, not a covalent bond to a hydrogen atom. It results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom and another very electronegative atom.

8 0

3 years ago

Assuming constant pressure, rank these reactions from most energy released by the system to most energy absorbed by the system,

gayaneshka [121]

Answer:

B > D > C > A

Explanation:

For the first law of the thermodynamics, the total energy variation in a process is:

ΔU = Q - W

Where Q is the heat, and W the work. If the system loses heat, Q < 0, if it absorbs heat, Q>0. If work is done in the system (volume decreases), W < 0, if the system does the work (volume increases), W > 0.

A. If the surroundings get colder, the system is absorbing heat, so Q>0, and the system decreases in volume so W < 0 :

ΔU = +Q - (-W) = +Q + W (absorbs a higher energy)

B. If the surroundings ger hotter, the system is losing heat, so Q<0, and the system expands, so W>0:

ΔU = -Q -W (loses higher energy)

C. Surroundings get hotter, Q<0, and the system decreases in volume, W<0

ΔU = - Q + W = 0 (magnitude of heat and work is similar)

D. Surroundings get hotter, Q<0, and the system is not changing in volume, W = 0.

ΔU = -Q (loses energy)

For the most released (more negative) for the most absorbed (most positive):

B > D > C > A

3 0

3 years ago