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Ivan
3 years ago
9

How many significant figures in 890

Chemistry
1 answer:
Kamila [148]3 years ago
8 0

Answer:

890 has 2 significant figures

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A glass marble is rubbed against a piece of silk. As a result the piece of fabric acquires extra electrons. What happens to the
Natalija [7]

Answer:

There was an electron transfer where the marble has lost the same amount of electrons (being positively charged) that the piece of silk has gained (being negatively charged).

Explanation:

As a result of this transfer of electrons and the charges induced in the objects they will attract.

When a body is endowed with electrical properties, that is, it acquires electrical charges, it is said to have been electrified.

Electrification is one of the phenomena that studies electrostatics.

To explain how static electricity originates, we must consider that matter is made of atoms, and atoms of charged particles, a nucleus surrounded by a cloud of electrons. Normally, matter is neutral (not electrified), it has the same number of positive and negative charges.

Some atoms are easier to lose their electrons than others. If a material tends to lose some of its electrons when it comes into contact with another, it is said to be more positive in the Triboelectric series. If a material tends to capture electrons when it comes into contact with another material, that material is more negative in the triboelectric series.

4 0
3 years ago
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Match the chemical Equation with his correct type
Alex

Answer:

The answer to your question is given below

Explanation:

1. C. 2NaCl + I2 —> 2NaI + Cl2 => C. Single displacement.

From the above equation, we can see that I2 replaces Cl in NaCl to produce NaI. This is simply called a single displacement reaction.

2. E. 2C4H10 + 13O2 —> 8CO2 + 10H2O => E. Combustion.

The above equation shows the burning of Hydrocarbon in the presence of O2. This is simply called Combustion as CO2 and H2O is produced.

3. D 2H2O —> 2H2 + O2 => D. Decomposition.

From the above equation, we can see that a single compound H2O produces two elements H2 and O2. This is simply called a decomposition reaction.

4. A. ZnS + 2HCl —> ZnCl2 + H2S => A. Double Decomposition.

From the above equation, we can see that Cl replaces S in ZnS to produce ZnCl2 and S replaces Cl in HCl to produce H2S. This is simply called double displacement reaction.

5. B. H2 + Br2 —> 2HBr => B. Synthesis.

From the above equation, we can see that two element H2 and Br2 combine to produce a single compound HBr. This is simply called a synthesis reaction.

7 0
2 years ago
Makes up the core of the other planets<br> stars with an M and ends with E
Sonbull [250]

Answer:

its iron not m or e

Explanation:

3 0
2 years ago
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How to draw Hess' Cycle for this question ?
NISA [10]

Answer : The standard enthalpy of formation of ethylene is, 51.8 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of C_2H_4 will be,

2C(s)+2H_2(g)\rightarrow C_2H_4(g)    \Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

(1) C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)     \Delta H_1=-1411kJ/mole

(2) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_2=-393.7kJ/mole

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_3=-285.9kJ/mole

Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equations, we get :

(1) 2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g)     \Delta H_1=+1411kJ/mole

(2) 2C(s)+2O_2(g)\rightarrow 2CO_2(g)    \Delta H_2=2\times (-393.7kJ/mole)=-787.4kJ/mole

(3) 2H_2(g)+2O_2(g)\rightarrow 2H_2O(l)    \Delta H_3=2\times (-285.9kJ/mole)=-571.8kJ/mole

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(+1411kJ/mole)+(-787.4kJ/mole)+(-571.8kJ/mole)

\Delta H=51.8kJ/mole

Therefore, the standard enthalpy of formation of ethylene is, 51.8 kJ/mole

7 0
2 years ago
Help ASAP 40 pts If answer 6
Olenka [21]

Answer:

1. B

2. C.

3. C

4. C.

5. A

6. B

Explanation:

i think?

3 0
3 years ago
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