Identify these element:a non-metal in the same group as leads?

A gas occupies a volume of 60 L at a temperature of 0.5 K. What will the volume be at 4 K?

Flauer [41]

Answer:

480 L

Explanation:

In order to solve this question, you should be familiar with gas laws. (I will attach a picture showing all of them under my answer.) In this question in particular, however, we only need Charles's Law because we're dealing with temperature and volume.

As we can see, Charles's Law is:

$\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

or, initial volume over initial temperature equals final volume over final temperature.

In this question, 60 L is our initial volume, and 0.5 K is our initial temperature (K being Kelvin). We are only given 4 K as our final temperature. We are asked to solve for the final volume. Let's set up the equation and solve for $V_{2}$ :

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(60) / (0.5) = $V_{2}$ / (4)

↓

120 = $V_{2}$ / 4

×4 ×4

↓

$V_{2}$ = 480 L

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There's our answer! Feel free to comment if you have any questions about my answer :)

3 0

3 years ago

Iron(II) chloride is formed from the reaction between iron and copper(II) chloride. Fe + CuCl2 FeCl2 + Cu If the reactants have

elena55 [62]

Answer: see figure attached and explanation below.

Explanation:

1) Chemical equation (given):

Fe + CuCl₂ → Cu + FeCl₂

2) ΔHf reactants: -256 kJ/mol (given)

3) ΔHf products: - 321 kJ/mol (given)

4) ΔH reaction = ΔHf products - ΔHf reactants = - 321 kJ/mol - (- 256 kJ/mol) = - 65 kJ/mol

5) Conclusion:

i) Since ΔHf of products is less (more negative) than ΔHf of reactants, the reaction is exhotermic: the reaction released energy, which is the reason why the products content less potential energy than the reactants.

ii) Then, the energy diagram is the typical one of an exothermic reaction: the products start a certain potential energy level, the energy incrases until reaching the activation energy (the energy barrier to form the activated complex) and then energy decreases until a level below the energy of the reactants.

iii) See the attached figure with such kind of diagram showing the products at a lower level than the reactans