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Bas_tet [7]
3 years ago
10

Yo 9th grade algebra 2 just answer the bottom row i did the rest by myself.

Mathematics
1 answer:
lilavasa [31]3 years ago
6 0

Answer:

5. (x-8)(x+2)

10. (x-5)(x-5) OR (x-5)^2

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Line segment AB has endpoints A(-1.5, 0) and B(4.5 8). Point C is on line segment AB located at (0, 2)
Pie

Answer:

The ratio of AC/CB=1/3

Step-by-step explanation:

We use the section formula:

(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})

We substitute the point A(-1.5,0) and B(4.5,8).

We plug in the points to get:

(\frac{4.5m - 1.5n}{m+n},\frac{8m+n \times 0}{m+n})

This is supposed to be equal to: (0,2).

(\frac{4.5m - 1.5n}{m+n},\frac{8m+n \times 0}{m+n}) = (0,2)

We can equate, corresponding coordinates to find m and n.

\frac{4.5m - 1.5n}{m + n}  = 0

This implies that:

4.5m - 1.5n = 0

4.5m  = 1.5n

\frac{m}{n}  =  \frac{1.5}{4.5}

\frac{m}{n}  =  \frac{1}{3}

Therefore the ratio is m:n=1:3

4 0
2 years ago
What is the answer to 3 times 1 plz write correct answer
il63 [147K]

Answer:

3

Step-by-step explanation:

the answer to 3 times 1 is 3

7 0
2 years ago
Can someone please help me with this question?
sattari [20]
The answer would be y=1/7x-4
7 0
2 years ago
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Hint: the
Julli [10]

Answer:

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. 16)n = 182, x = 135; 95 percent

✓ 16)n = 182, x = 135; 95 percent sample proportion: p-hat = 135/182 = 0.74 E = 1.96*sqrt[0.74*0.26/182] = 0.0637 95% CI: 0.74-0.0637 < p < …

6 0
2 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.
faltersainse [42]

Answer:

V = 34,13*π   cubic units

Step-by-step explanation: See Annex

We find the common points of the two curves, solving the system of equations:

y²  = 2*x                           x = 2*y  ⇒  y = x/2

(x/2)² = 2*x

x²/4 = 2*x

x  =  2*4         x  = 8      and   y = 8/2       y = 4

Then point  P ( 8 ;  4 )

The other point Q is  Q ( 0; 0)

From these  two points, we get the integration limits for dy ( 0 , 4 )are the integration limits.

Now with the help of geogebra we have: In the annex segment ABCD is dy then

V = π *∫₀⁴ (R² - r² ) *dy   =  π *∫₀⁴ (2*y)² - (y²/2)² dy =  π * ∫₀⁴ [(4y²) - y⁴/4 ] dy

V = π * [(4/3)y³ - (1/20)y⁵] |₀⁴

V =  π * [ (4/3)*4³ - 0 - 1/20)*1024 + 0 )

V = π * [256/3  - 51,20]

V = 34,13*π   cubic units

3 0
2 years ago
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