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EleoNora [17]
3 years ago
15

Which table shows a proportional relationship between a and b? a b 3 9 4 12 5 20 a b 20 25 24 30 32 40 a b 4 12 5 15 6 24 a b 3

4 6 9 12 16
Mathematics
1 answer:
umka21 [38]3 years ago
8 0
When the second number is divided by the first, the result is ...

First table
   9/3 = 3
   12/4 = 3
   20/5 = 4 . . . . result is not consistent. NOT a proportional relationship

Second table
   25/20 = 1.25
   30/24 = 1.25
   40/32 = 1.25 . . . . result is consistent. A PROPORTIONAL RELATIONSHIP

Third table
   12/4 = 3
   15/5 = 3
   24/6 = 4 . . . . result is not consistent. NOT a proportional relationship

Fourth table
   4/3 ≈ 1.33
   9/6 = 1.5
   16/12 ≈ 1.33 . . . . result is not consistent. NOT a proportional relationship
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What is the 32nd term of 311, 305, 299
nata0808 [166]

Answer:

503

Step-by-step explanation:

For an arithmetic sequence, the n-th term is found by

a_n = a_1 + (n - 1)d

To find d (the common difference) we can simply subtract one of the terms by the last, for example:

d = 299 - 305 \\d = -6 \\

The common difference must be the same throughout the entire sequence, so we can do it once more just to be sure:

d = 305 - 311\\d = -6

We also have to know that a_1 stands for the first term of the sequence, which in this case is 311.

Now that we know this, let's find the 32nd term

a_{32} = 311 + (32 - 1)-6\\a_{32} = 311 + 192\\a_{32} = 503

Good luck!

4 0
2 years ago
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The difference between three times a number and 7 is 14
Stels [109]
3x -7 = 14

3x - 7 (+7) = 14 (+7)

3x = 21

3x/3 = 21/3

x = 7

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6 0
3 years ago
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Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

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2 years ago
Assertion - if the mean of five observations X, X+2, X+4, X+6, X+8 is 11 then,Mean of last 3 observations is 8. Reason - Range=
FinnZ [79.3K]
A is false but R is true (the mean of the last 3 values is not 8 since x=7)
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2 years ago
What is the reason for Statement 5 of the two-column proof?
zmey [24]

Given: ∠JNL and ∠MNK are vertical angles and  m∠MNK=90°

Prove: ∠JNL is a right angle.

   Statements                                                     Reasons

1.  ∠JNL and ∠MNK are vertical angles.             Given

2. \angle JNL \cong \angle MNK        Vertical angle theorem

3. m \angle JNL = m \angle MNK        Angle congruence postulate

4.  m \angle MNK = 90^\circ                Given

5. m \angle JNL = 90^\circ                 <u> Substitution Property of Equality</u>

Since, the measures of angle JNL and MNK are equal and the measure of angle MNK is 90 degrees. therefore, by substitution property of equality, both the angles JNL and MNK will have an equal measure.

Therefore,  m \angle JNL = 90^\circ

6. ∠JNL is a right angle.                                     Definition of right angle

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