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EleoNora [17]
3 years ago
15

Which table shows a proportional relationship between a and b? a b 3 9 4 12 5 20 a b 20 25 24 30 32 40 a b 4 12 5 15 6 24 a b 3

4 6 9 12 16
Mathematics
1 answer:
umka21 [38]3 years ago
8 0
When the second number is divided by the first, the result is ...

First table
   9/3 = 3
   12/4 = 3
   20/5 = 4 . . . . result is not consistent. NOT a proportional relationship

Second table
   25/20 = 1.25
   30/24 = 1.25
   40/32 = 1.25 . . . . result is consistent. A PROPORTIONAL RELATIONSHIP

Third table
   12/4 = 3
   15/5 = 3
   24/6 = 4 . . . . result is not consistent. NOT a proportional relationship

Fourth table
   4/3 ≈ 1.33
   9/6 = 1.5
   16/12 ≈ 1.33 . . . . result is not consistent. NOT a proportional relationship
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Which diagram shows lines that must be parallel lines cut by a transversal? 2 horizontal lines are intersected by a third line.
ivanzaharov [21]

Answer:

  (A)  At the intersection of the first line with the third line, the bottom left angle is 115 degrees. At the intersection of the second line with the third line, the uppercase left angle is 65 degrees.

Step-by-step explanation:

Alternate interior angles are supplementary when parallel lines are crossed by a transversal. The first description seems to be describing alternate interior angles. (See attachment)

_____

<em>Comment on orientation</em>

If the transversal is oriented horizontally, then the descriptions of the angles will be of different angles than assumed here.

8 0
4 years ago
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Answer for the points<br> 6 − (9 − 2) + 3 × 6
AfilCa [17]

Answer:

17

Step-by-step explanation:

USING BIDMAS (Brackets Indices Division Multiplication Addition Subtraction)

6 − (9 − 2) + 3 × 6

9-2=7

3x6=18

6-7+18=17

8 0
3 years ago
3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
Liz flips a coin 30 times. The coin lands heads up 21 times and tails up 9 times. Complete each
SSSSS [86.1K]

Answer:

Pr = 0.50

Step-by-step explanation:

Given

n = 30

H = 21

T = 9

See attachment for complete question

Required

P(H)

The question requires that we calculate the theoretical probability of landing on the head.

This means that, we have to ignore the given data, and we use the following

S =\{H,T\} --- sample space

n(S) = 2 --- sample size

n(H) = 1 --- occurrence of Head

So, the theoretical probability is:

Pr = n(H)/n(S)

Pr = 1/2

Pr = 0.50

8 0
3 years ago
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lidiya [134]

Answer:

27.9 dollars

Step-by-step explanation:

2.70= 15 percent

2.70x2=5.4=30 percent

5.4+2.70=8.1=45 percent

8.1x2=16.2=95 percent

95 percent + 15 percent=18.9

18.9=105 percent

in order to subtract 5 percent we need to find 5 percent by dividing 2.70 by 3

which = .9

18.9+9=27.9

100 percent is 27.9 dollars

4 0
3 years ago
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