1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
djverab [1.8K]
3 years ago
7

A rope has one end tied to a vertical support. You hold the other end so that the rope is horizontal. If you move the end of the

rope back and forth with a frequency of 4 Hz, the transverse wave you produce has a wavelength of 0.5 m. What is the speed of the wave in the rope?4 m/s0.13 m/s8 m/s2 m/s
Chemistry
1 answer:
Lady_Fox [76]3 years ago
5 0

Answer:

  • The speed of the wave in the rope is 2 m/s

Explanation:

1. <u>Data</u>:

a) ν = 4 Hz

b) λ = 0.5 m

c) s = ?

2. <u>Physical principles and formula</u>:

The propagation of waves in a rope is a classical example of <em>transverse waves</em>: the pulse is inflected in the <em>vertical</em> direction and the wave travels in the <em>horizontal</em> direction, i.e. the pulse or vibration is perpendicular to the motion of the media particles.

The equation that relates <em>speed (s), wavelength (λ), frequency (ν) </em>is:

  •            distance     = speed ×      time
  •          wavelength = speed  × period
  •           wavelenfth = speed / frequency
  •                    λ         =      s     /        ν
  •               meter      = (meter/second)  /   second⁻¹
  •                   m        = (m /s) / s⁻¹

3. <u>Solution</u>:

  • λ = s / ν⇒ s = λ·ν
  • s = 0.5 m × 4 Hz = 2 m/s
You might be interested in
The ph of coffee is 5.6. The ph of grapefruit juice is 2.6. This means that the proton concentration in coffee is
Brrunno [24]

pH scale is used to measure the acidity or alkalinity on a scale of 0-14 where 0-6.9 is the acidic region , 7.1-14 is the basic region and 7 is for the neutral substance. We can calculate the concentration of proton from pH.

pH=-log[H^+]  

where [H^+] is the concentration of proton

As per the question ,the pH of coffee is 5.6 and we need to find the concentration of proton so putting the values in the above equation, we get

5.6=-log[H^+]

-5.6=log[H^+]

antilog(-5.6)= [H^+]

[H^+]= 2.511\times10^-^6 M

6 0
3 years ago
A student performed a serial dilution on a stock solution of 1.33 M NaOH. A 1.0 mL aliquot of the stock NaOH (ms) was added to 9
serg [7]

Answer:

The correct answer is 1.33 x 10⁻⁵ M

Explanation:

The concentration of the stock solution is: C= 1.33 M

In the first dilution, the student added 1 ml of stock solution to 9 ml of water. The total volume of the solution is 1 ml + 9 ml = 10 ml. So, the first diluted concentration is:

C₁= 1.33 M x 1 ml/10 ml = 1.33 M x 1/10 = 0.133 M

The second dilution is performed on C₁. The student added 1 ml of 0.133 M solution to 9 ml of water. Again, the total volume is 1 ml + 9 ml = 10 ml. The second diluted concentration is:

C₂= 0.133 M x 1 ml/10 ml = 0.133 M x 1/10= 0.0133 M

Since the student repeated the same dilution process 3 times more (for a total of 5 times), we have to multiply 5 times the initial concentration by the factor 1/10:

Final concentration = initial concentration x 1/10 x 1/10 x 1/10 x 1/10 x 1/10

                                = initial concentration x (1/10)⁵

                                = 1.33 M x 1 x 10⁻⁵

                                = 1.33 x 10⁻⁵ M

3 0
3 years ago
If 5.57 g of Ag2O is sealed in a 75.0-mL tube filled with 760 torr of N2 gas at 28 ∘C, and the tube is heated to 310 ∘C, the Ag2
Snezhnost [94]

Answer: Total pressure = 7293.2 torr or 9.60 atm

Explanation:

<em>Total pressure = partial pressure of nitrogen + partial pressure of oxygen</em>

The partial pressure due to nitrogen is determined using the equation of Gay-Lussac's law: <em>P₁/T₁=P₂/T₂</em>

P₁ = 760 torr = 1atm, T₁ = 28∘C = (273+28)K = 301k, P₂ = ?, T₂ = 310∘C =(310+273)K = 583K

P₂ = P₁ T₂/ T₁

P₂ = 760 * 583 / 301 = 1472.03 torr

The pressure due to Oxygen gas produced is calculated thus:

Balanced equation of the decomposition of Ag₂O at s.t.p. is as follows;

2Ag₂O ----> 4Ag + O₂(g)

2 moles of Ag₂O produces 1 mole of O₂

molar mass of Ag₂O = (2*108 + 16)g = 232g/mol

molar volume of gas at s.t.p. = 22.4L

2*232g i.e. 464g of Ag₂O produces 22.4L of O₂

5.57g of Ag₂O will produce 5.57g*22.4L/464g = 0.269L or 269mL of O₂

Using the General gas equation  P₁V₁/T₁=P₂V₂/T₂

P₁ = 1atm = 760 torr, V₁ = 269mL, T₁=273K, P₂ = ?, V₂= 75mL, T₂ = 583K

P₂ = P₁V₁T₂/V₂T₁

P₂ = 760*269*583 / 75*273

P₂ = 5821.17 torr

Total pressure = (1472.03 + 5821.17) torr

Total pressure = 7293.2 torr or 9.60 atm

7 0
3 years ago
Assume at exactly 100.0°c and 1.00 atm total pressure, 1.00 mole of liquid water and 1.00 mole of water vapor occupy 18.80 ml an
Grace [21]

Answer 1) : When we calculate the ΔQ = -40.66 kJ (heat of vaporisation).


Then, we can relate the work done with this equation,

ΔW = -PΔV

First we need to calculate the volume, which will be,


Volume of water vapor = (nRT) / (P)

Then, V = (1 mole) X (0.0821 L X atm/mole X K) X (373.15K) / (1atm) = 30.6 liters So, it is given, and verified.


Volume of Water can be used for finding the; Density = M / V

D = ( 1 mole) X (18.02 g/mole) / (18.80 mL) = 0.9585 g/mL

On, substituting the values, we get,


ΔW = -PΔV

Work = - (1 atm) X (0.00188L - 30.62L) X 0.1013kJ/L X atm = 3.10 kJ


hence the work done is 3.10 kJ


Answer 2) Now, for calculating the internal energy, we can use the formula as,

ΔE = ΔQ + ΔW


Here, we have the values of ΔQ = -40.66 kJ and ΔW as = 3.10 kJ


So, we get, ΔE = (-40.66) + (3.10) = - 37.55 kJ


Therefore, the change in the internal energy will be -37.55 kJ.



3 0
3 years ago
Evolution happens by which process?
ivanzaharov [21]

Answer:

a

Explanation:

7 0
3 years ago
Other questions:
  • A 2.5 g copper penny is given a charge of 4.0x10-9
    15·1 answer
  • 15. What is the name of Fl-?<br> A)Fluorous ion<br> B)Fluorine<br> C)Fluoride ion<br> D)Fluorine ion
    8·1 answer
  • Suppose 0.829g of zinc chloride is dissolved in 100.mL of a 0.60M aqueous solution of potassium carbonate. Calculate the final m
    13·1 answer
  • Using the following bond energies:
    14·1 answer
  • Rank these acids according to their expected pKa values.ClCH2COOHClCH2CH2COOHCH3CH2COOHCl2CHCOOHIn order of highest pka to lowes
    13·1 answer
  • Perform the following operation
    14·1 answer
  • What is the volume of a cube that has a mass of 52.3g and a density of 1.25 g/mL
    14·1 answer
  • The girl I liked just asked me who I liked.
    14·2 answers
  • PLEASE HELP!
    10·1 answer
  • Can anyone help me at this please anyone?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!