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sashaice [31]
3 years ago
14

Using the following bond energies:

Chemistry
1 answer:
uranmaximum [27]3 years ago
4 0

Answer:

The answer is "Option b".

Explanation:

Given equation and value:

\Rightarrow C_2H_2 \ (g)+ \frac{5}{2}O_2 \ (g) \longrightarrow 2CO_2\ (g)+H_2O\ (g)

\left\begin{array}{ccc}C \equiv  C&839\\C-H &413\\O=O &495\\ C=O &799\\ O-H &467 \end{array}\right \\\\

calculating equation value:

\Rightarrow 839 + 2(413) +\frac{5}{2} (495) \longrightarrow 2(2)799+2 \times 467 +E

\Rightarrow 839 + 826 +1237.5 = 3196+934 +E\\\\\Rightarrow 2902.5 =4130 +E\\\\\Rightarrow 2902 = 4130 +E\\\\\Rightarrow 2902 - 4130 +E\\\\\Rightarrow E = -1228 \ KJ \\\\

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4 years ago
Cuáles son las costumbres de Dosquebradas​
serious [3.7K]

Answer:

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Explanation:

6 0
3 years ago
I don't understand how to solve.
mr Goodwill [35]

Answer:

1. b. increase [NH3].

2. d. 0.01.

Explanation:

Hello!

In this case, for these equilibrium problems, we proceed as follows:

1. Here, we consider the Le C hatelier 's principle applied to a gas-phase reaction in which the reactants side have more number of moles; therefore, increasing the pressure will increase the products side as it has the fewest number of moles, so the answer is b. increase [NH3].

2. Here, we know that the equilibrium constant of the reverse reaction equals the inverse of the equilibrium constant of the forward reaction, thus, we obtain:

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Best regards!

5 0
3 years ago
In a perfect world, reactions can never go above 100% yield. However in reality you will sometimes get above 100% yield. Why?
iris [78.8K]

Answer:

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6 0
2 years ago
53. A firefighter of mass 80 kg slides down a vertical pole
Zielflug [23.3K]

Answer:

Answer is given below:

Explanation:

<em>Given Data:</em>

mass = 80kg

acceleration = 4 ms

force = 800N

<em>Find out:</em>

friction = ?

<em>Formula</em><em>:</em>

F-friction = weight - f-net

<em>Solution:</em>

weight = (80)(10)

           = 800 N

F-net = ma =(80)(4) = 320N

F-friction = weight - F-net

               =800 N - 320N

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<em>Answer</em> :

Friction = 480 N

   

6 0
3 years ago
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