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blsea [12.9K]
3 years ago
5

A triangle with sides of lengths 9, 22, and 24 is a right triangle

Mathematics
1 answer:
Leona [35]3 years ago
4 0

Answer:

The statement is false

Step-by-step explanation:

we know that

if the triangle is a right triangle

then

the triangle must satisfy the Pythagoras Theorem

c^{2}=a^{2}+b^{2}

we have

c=24\ units

a=9\ units

b=22\ units

substitute

24^{2}=9^{2}+22^{2}

576=81+484

576 \neq 565

therefore

Is not a right triangle

The statement is false

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Answer:

f(2)=5

f(5)=33

Step-by-step explanation:

The given formula, that recursively defines the sequence is

f(1) = 3 \\ f(n + 1) = 2f(n) - 1

When n=1, we obtain;

f(1+ 1) = 2f(1) - 1 \\ f(2) = 2 \times 3 - 1 \\ f(2) = 6 - 1 \\ f(2) = 5

When n=2, we get:

f(2+ 1) = 2f(2) - 1 \\ f(3) = 2 \times 5 - 1 \\ f(3) = 10 - 1 \\ f(3) = 9

When n=3,

f(3 + 1) = 2f(3) - 1 \\ f(4) = 2f(3) - 1 \\ f(4) = 2 \times 9 - 1 \\ f(4) = 18 - 1 \\ f(4) = 17

When n=4

f(4 + 1) = 2 f(4) - 1 \\ f(5) = 2 \times 17 - 1 \\ f(5) = 34 - 1 \\ f(5) = 33

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f(6) = 65

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