Question

In ΔMNO, the measure of ∠O=90°, MO = 15, ON = 8, and NM = 17. What ratio represents the cosine of ∠N?

Answer 1

Answer: The required ratio would be $8:17.$

Step-by-step explanation:

Since we have given that

∠O=90°,

MO = 15, (Perpendicular)

ON = 8, (Base) and

NM = 17 (Hypotenuse)

So, we need to find the cosine of ∠N.

As we know that

$\cos N=\dfrac{Base}{Hypotenuse}\\\\\cos N=\dfrac{8}{17}$

Hence, the required ratio would be $8:17.$