2(10)-2(6x)= x-8x
20-12x=x-8x
+12x+12x
20=13x-8x
20=5x
4=x
Firstly expand (x - 3)(ax^2 + bx + c):
ax^3 + bx^2 + cx - 3ax^2 - 3bx - 3c
Now rearrange it so that it's in the form ax^3 + bx^2 + cx + d:
ax^3 + (b-3a)x^2 + (c-3b)x - 3c
Now we can compare both equations:
ax^3 + (b-3a)x^2 + (c-3b)x - 3c = 2x^3 - x^2 - 19x + 12
We get:
(1) a = 2
(2) b - 3a = -1
(3) c - 3b = -19
(4) -3c = 12
If we substitute (1) into (2) we get:
b - 3*2 = -1
b - 6 = -1
b = 5
Now if we solve (4) we get:
-3c = 12
c = -4
Therefor a = 2, b = 5 and c = -4
Answer:
C
Step-by-step explanation:
Ax+by= C
Ax -Ax +By = C -Ax
By = C-Ax
By/B = C-Ax/B
y= C-Ax/B
Answer:
0.6 x 94, 60/100 x 94
Step-by-step explanation:
0.6 = 60% of 1.
60/100 also = 60% of 1
