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3 years ago

PLEASE HELP ME FIGURE THIS OUT 1.

Mathematics

1 answer:

OlgaM077 [116]3 years ago

3 0

Answer: $\frac{7\pi}{12}$ , II, $\frac{5\pi}{12}$

Step-by-step explanation:

a) $-\frac{41\pi}{12}$

Add 2π until you receive a positive number. 2π = $\frac{24\pi}{12}$

$-\frac{41\pi}{12}$ + $\frac{24\pi}{12}$ = $-\frac{17\pi}{12}$

$-\frac{17\pi}{12}$ + $\frac{24\pi}{12}$ = $\frac{7\pi}{12}$

b) $\frac{\pi}{2}$ < $\frac{7\pi}{12}$ < π So it is located in Quadrant II

c) It is closest to the x-axis at π. π - $\frac{7\pi}{12}$ = $\frac{5\pi}{12}$

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Answer: π, (-1, 0), A, 0

Step-by-step explanation:

a) -7π

Add 2π until you receive a positive number.

-7π + 2π = -5π

-5π + 2π = -3π

-3π + 2π = -π

-π + 2π = π

b) Look at the Unit Circle to find that π is located at (-1, 0)

c) x = -1, y = 0, r = 1

sin θ = $\frac{y}{r}$

d) sin θ = $\frac{y}{r}$ = $\frac{0}{1}$ = 0

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Answer: 7π

Step-by-step explanation:

s = rθ

= 35 $(\frac{\pi}{5})$

= 7π

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