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Andru [333]
3 years ago
12

PLEASE HELP ME FIGURE THIS OUT 1.

Mathematics
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer: \frac{7\pi}{12}, II, \frac{5\pi}{12}

<u>Step-by-step explanation:</u>

a) -\frac{41\pi}{12}

Add 2π until you receive a positive number. 2π = \frac{24\pi}{12}

-\frac{41\pi}{12} + \frac{24\pi}{12} = -\frac{17\pi}{12}

-\frac{17\pi}{12} + \frac{24\pi}{12} = \frac{7\pi}{12}

b) \frac{\pi}{2} < \frac{7\pi}{12} < π So it is located in Quadrant II

c) It is closest to the x-axis at π.  π - \frac{7\pi}{12}  = \frac{5\pi}{12}

**************************************************************************

Answer: π, (-1, 0), A, 0

<u>Step-by-step explanation:</u>

a) -7π

Add 2π until you receive a positive number.

-7π + 2π = -5π

-5π + 2π = -3π

-3π + 2π = -π

-π + 2π = π

b) Look at the Unit Circle to find that π is located at (-1, 0)

c) x = -1, y = 0, r = 1

sin θ = \frac{y}{r}

d) sin θ = \frac{y}{r} = \frac{0}{1} = 0

**************************************************************************

Answer: 7π

<u>Step-by-step explanation:</u>

s = rθ

 = 35(\frac{\pi}{5})

 = 7π

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