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valentinak56 [21]
4 years ago
7

How many miles of silver nitrate do 2.888 x 10^15 formula units equal?

Chemistry
1 answer:
Furkat [3]4 years ago
5 0

Answer: 4.8x10^-9 mol

Explanation:

1mole of Silver nitrate contains 6.02x10^23 molecules

Therefore, Xmol of silver nitrate will contain 2.888x10^15 molecules i.e Xmol of silver = 2.888x10^15/6.02x10^23 = 4.8x10^-9 mol

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C3H8 + 5 O2 → 3 CO2 + 4 H2O
Nataly [62]

Answer:

¹/3 C3H8(g) + ⁵/3 O2(g)

Explanation:

The coefficient before every molecule is representative of the number of moles. We can represent it in ration form so as to calculate the question;

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l) means;

For every 1 mole of C₃H₈(g) and 5 moles of  O₂(g) produces  3 moles of  CO₂(g) and 4 moles of H₂O(l).

Therefore to produce 1.00 mole of CO₂(g);

We represent it in ratio;

C₃H₈(g) : CO₂(g)

1  :     3

For more on evaluating moles in chemical reactions check out;

brainly.com/question/13967925

brainly.com/question/13969737

7 0
3 years ago
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Will ice melt faster with a lot of salt added or little salt added?
STatiana [176]

Answer:

alot

Explanation:

because salt contains stuff

5 0
3 years ago
A car rolls down a ramp. What is the force acting on the car that causes the movement down the ramp? A) acceleration B) centripe
Ann [662]
The answer for the question is D.
7 0
4 years ago
What is happening to the particles in a substance during evaporation?
AysviL [449]
During evaporation, liquid particles on the surface momentarily gain enough energy due to random thermal motion to overcome the intermolecular attractions and escape into the gas phase. These evaporating particles, by virtue of gaining energy, also increase in velocity.

Thus, the correct answer here would be the third choice.
8 0
3 years ago
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Given 200ul of a 0.5mg/ml stock solution of BSA, how much do you pipet into a test tube so that you are adding 5ug of BSA to the
Trava [24]

<u>Answer: </u>10\mu L of volume needs to be pipetted out in the test tube.

<u>Explanation:</u>

We are given:

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Volume of stock solution = 200\mu L=0.2mL    (Conversion factor: 1mL=1000\mu L

It is also given that for the mass of BSA is 0.5 g, the volume used up is 1 mL

In order to have, 0.005 g, the volume of stock solution needed will be = \frac{1mL}{0.5g}\times 0.005g=0.01mL=10\mu L

Hence, 10\mu L of volume needs to be pipetted out in the test tube.

3 0
3 years ago
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