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prisoha [69]
3 years ago
8

If you could zoom enough to see atoms how would u find out if it is a compound element or a

Chemistry
1 answer:
scoundrel [369]3 years ago
4 0
You would be able to tell because a compound has two or more different atoms bonded together. The element only has 1 type of atom. and the mixture has two or more different atoms together but not joined!!
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Which equation is balanced?
Simora [160]

the 1st one is balanced, the 2nd isn't (the number of Mg differs from left 1 to right 2).

The third is also not balanced, 2 F left,2*3=6 on the right

3 0
3 years ago
A sample of gas occupies a volume of 67.5 mL . As it expands, it does 131.0 J of work on its surroundings at a constant pressure
baherus [9]

Answer:

The final volume V2=1.3175L

Explanation:

between work ( w), pressure ( P ) and volume ( V ) is the following:

w=−PΔV

where,

ΔV=V2−V1

It was stated that the gas is expanding, then the work is done by the system and it is of a negative value .

Note that work, should be expressed in 1L⋅atm=101.3J

CHECK THE ATTACHMENT FOR DETAILED EXPLATION

4 0
4 years ago
20.1 g of aluminum and 219 g of chlorine gas react until all of the aluminum metal has been converted to AlCl3. The balanced equ
Romashka-Z-Leto [24]

Answer:

<em>The amount of Cl2 gas left , after the reaction goes to completion is : </em><u><em>139.655 grams</em></u>

Explanation:

Molar mass : It is the mass in grams present in one mole of the substance.

Moles of the substance is calculated by:

Moles=\frac{Mass}{Molar\ mass}

2Al(s)+3Cl_{2}(g)\leftarrow 2AlCl_{3}(g)

According  to this equation:

2 mole of Al = 3 mole of Cl2 = 2 mole of AlCl3

Molar mass of Al = 27.0 g/mol

Mass of Al = 20.1 gram

Moles of Al present in the reaction :

Moles=\frac{Mass}{Molar\ mass}

Moles=\frac{20.1}{26.98}

Moles of Al = 0.744

Similarly calculate the moles of Cl2

Molar mass of Cl2 = 71.0 g/mol

Mass = 219 gram

Moles=\frac{Mass}{Molar\ mass}

Moles=\frac{219}{70.98}

Moles of Cl2 = 3.08 moles

According to equation,

2 mole of Al reacts with = 3 mole of Cl2

1 moles of Al reacts with = 3/2  mole of Cl2

0.744 moles of Al reacts with = 3/2(0.744) moles of Cl2

= 1.116 moles of Cl2

But actually present Cl2 = 3.08 moles

Hence Al is the limiting reagent , and Cl2 is the excess reagent.

The whole Aluminium Al get consumed during the reaction.

The amount of Cl2 in excess = Total Cl2 - Cl2 consumed

Cl2 in excess = 3.08 - 1.116 = 1.964 moles

<u>Cl2 in grams</u><u> </u>= 1.964 x 70.90 <u>= 139.655 grams</u>

6 0
4 years ago
When driving a truck , is fuel crucial why or why not ?
myrzilka [38]
Yes because you have to use fuel to drive that's my guess
3 0
4 years ago
Read 2 more answers
Calculate the mass of Octane needed to release 6.20 mol Co2
n200080 [17]
The combustion reaction of octane is as follow,

                           C₈H₁₈  +  25/2 O₂     →     8 CO₂  +  9 H₂O

According to balance equation,

8 moles of CO₂ are released when  =  114.23 g (1 mole) Octane is reacted

So,

      6.20 moles of CO₂ will release when  =  X g of Octane is reacted

Solving for X,
                                     X  =  (114.23 g × 6.20 mol) ÷ 8 mol

                                     X  =  88.52 g of Octane
Result:
           88.52 g of Octane is needed to release 6.20 mol CO₂.
8 0
3 years ago
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