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2 years ago

If you could zoom enough to see atoms how would u find out if it is a compound element or a

1 answer:

4 0

You would be able to tell because a compound has two or more different atoms bonded together. The element only has 1 type of atom. and the mixture has two or more different atoms together but not joined!!

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Yo peeps! Important question: What does the colors blue, purple, green, and yellow mean on a mood ring??

Ksivusya [100]

Blue usually means sadness, yellow is happiness, purple is calm, green is jealousy

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3 years ago

In which situation is the acceleration of the car negative?

Charra [1.4K]

B) The velocity of the car reduced from 50k/m over one min.

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3 years ago

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HELP PLS PLS PLS ILL MARK U BRAINLIEST

777dan777 [17]

Answer:

2 FeCl3 → 2 Fe + 3 Cl2

Explanation:

2 Fe and 6 Cl on the reactants side, and 2 Fe and 6 Cl on the products side.

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1 year ago

Two students performed the same experiment separately and each one of them recorded two readings of mass which are given below.

Lapatulllka [165]

Answer:

Hey weirdo what's up?

So you got a question huh?

Lemme answer

As said the correct reading is 3.0grams

And the option A has 3.01 and 2.99 which are very mush precise and accurate to 3.0 gram don't you think?

So the answer is

Option ii the result of students A is both precise and accurate

Loye ya

Peace out

5 0

2 years ago

Read 2 more answers

When a 3.25 g sample of solid sodium hydroxide was dissolved in a calorimeter in 100.0 g of water, the temperature rose from 23.

sertanlavr [38]

Answer : The enthalpy change for the solution is 42.8 kJ/mol

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $15.8J/^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m$ = mass of water = 100.0 g

$\Delta T$ = change in temperature = $T_2-T_1=(32.0-23.9)=8.1^oC$

Now put all the given values in the above formula, we get:

$q=[(15.8J/^oC\times 8.1^oC)+(100.0g\times 4.18J/g^oC\times 8.1^oC)]$

$q=3513.8J=3.5138kJ$ (1 kJ = 1000 J)

Now we have to calculate the enthalpy change for the solution.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 3.5138 kJ

m = mass of NaOH = 3.25 g

Molar mass of NaOH = 40 g/mole

$\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{3.25g}{40g/mole}=0.0812mole$

Now,

$\Delta H=\frac{3.5138kJ}{0.0821mole}=42.8kJ/mol$

Therefore, the enthalpy change for the solution is 42.8 kJ/mol

4 0

3 years ago