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Helen [10]
3 years ago
14

Given 200ul of a 0.5mg/ml stock solution of BSA, how much do you pipet into a test tube so that you are adding 5ug of BSA to the

test tube
Chemistry
1 answer:
Trava [24]3 years ago
3 0

<u>Answer: </u>10\mu L of volume needs to be pipetted out in the test tube.

<u>Explanation:</u>

We are given:

Mass of BSA to be formed = 5\mu g=0.005mg      (Conversion factor: 1mg=1000\mu g

Volume of stock solution = 200\mu L=0.2mL    (Conversion factor: 1mL=1000\mu L

It is also given that for the mass of BSA is 0.5 g, the volume used up is 1 mL

In order to have, 0.005 g, the volume of stock solution needed will be = \frac{1mL}{0.5g}\times 0.005g=0.01mL=10\mu L

Hence, 10\mu L of volume needs to be pipetted out in the test tube.

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The sample of argon gas that has the same number of atoms as a 100 milliliter sample of helium gas at 1.0 atm and 300 is 100. mL at 1.0 atm and 300. K

The correct option is D.

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The number of moles of gases in each of the given samples of gas is found below using the ideal gas equation.

The ideal gas equation is: PV/RT = n

where;

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n =  1 * 0.1 / 0.082 * 300

n = 0.00406 moles

For the argon gas sample:

A. n =  1 * 0.05 / 0.082 * 300

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C. n =  0.5 * 0.1 / 0.082 * 300

n = 0.00203 moles

D. n =  1 * 0.1 / 0.082 * 300

n = 0.00406 moles

Learn more about ideal gas equation at: brainly.com/question/24236411

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