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Helen [10]
3 years ago
14

Given 200ul of a 0.5mg/ml stock solution of BSA, how much do you pipet into a test tube so that you are adding 5ug of BSA to the

test tube
Chemistry
1 answer:
Trava [24]3 years ago
3 0

<u>Answer: </u>10\mu L of volume needs to be pipetted out in the test tube.

<u>Explanation:</u>

We are given:

Mass of BSA to be formed = 5\mu g=0.005mg      (Conversion factor: 1mg=1000\mu g

Volume of stock solution = 200\mu L=0.2mL    (Conversion factor: 1mL=1000\mu L

It is also given that for the mass of BSA is 0.5 g, the volume used up is 1 mL

In order to have, 0.005 g, the volume of stock solution needed will be = \frac{1mL}{0.5g}\times 0.005g=0.01mL=10\mu L

Hence, 10\mu L of volume needs to be pipetted out in the test tube.

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Which numbers are used? Consider the balanced chemical equation that follows. You are asked to determine how many moles of water
velikii [3]
I am assuming that the balanced equation is 
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Since the hydrogen is the limiting reagent (meaning if the hydrogen runs out the reaction stops), we need to compare the mole ratio between hydrogen and water.

The mole ratio between H₂ and H₂O is 2:2, or 1:1 (as seen on the coefficients of the balanced equation)
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4 years ago
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N a football game, two players tackle each other so hard that they both fly in opposite directions after they hit each other. �W
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Answer:

Newton's Third Law

Explanation:

Newton's Third Law stipulates that for every action there is an equal and opposite reaction.

So when the two players are tackling they exert a force on each other.

If player 1 tackles (exerts a force) player 2,  player 2 will exert an equal and opposite reaction on player 1 as stated in Newton's Third Law.

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3 years ago
Which of the following questions can be answered by science? (2 points) What makes a song sound beautiful? What is the meaning o
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4 years ago
a sealed container filled with argon gas at 35 c has a pressure of 832 torr. if the volume of the container is decreased by a fa
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Answer:

If the volume of the container is decreased by a factor of 2 the pressure is is increased by the same factor to 1664 torr.

Explanation:

Here we have Boyle's law which states that, at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure

V ∝ 1/P or V₁·P₁ = V₂·P₂

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From V₁·P₁ = V₂·P₂ we have,

P₂ = V₁·P₁/V₂ = V₁·P₁/(V₁/2)

P₂  = 2·V₁·P₁/V₁ = 2·P₁ = 2× 832 torr = 1664 torr

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3 years ago
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