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andreyandreev [35.5K]
3 years ago
9

East question, just making sure (picture)

Chemistry
1 answer:
S_A_V [24]3 years ago
8 0
I see that you already have an answer so I’m just typing for points
You might be interested in
Be sure to answer all parts. For each of the following pairs of elements, state whether the binary compound they form is likely
andrew-mc [135]

Answer:

(a) Covalent bond. NF₃ (nitrogen trifluoride)

(b) Ionic bond. LiCl (lithium chloride)

Explanation:

<em>(a) N and F</em>

Nitrogen and fluorine are nonmetals, with high and similar electronegativities, so they form covalent bonds, in which they share pairs of electrons to complete the octet in their valence shell. N has 5 valence electrons so it will form 3 covalent bonds while each Cl has 7 valence electrons so it will form 1 covalent bond. As a result, the empirical formula is NF₃ (nitrogen trifluoride).

<em>(b) Li and Cl</em>

Lithium is a metal and Chlorine is a nonmetal. They have different electronegativities so they form an ionic bond, in which Cl gains 1 electron (7 valence e⁻) and Li loses 1 electron (1 valence e⁻). The empirical formula is LiCl (lithium chloride).

5 0
3 years ago
What volume of 0.100 M HCl will react completely with 50.00 mL of 0.200 M NaOH?
skelet666 [1.2K]
Equation of reaction
Hcl+NaoH-->Nacl+H2O
1:1
Using the formula CaVa/CbVb=na/nb
Ca(Concentation of acid)= 0.100M
Cb(Concentration of base)=0.200M
Va=?
VB=50.00ml
na=1
nb=1
from the formula
Va= CbVbna/Canb
Va= 0.2*50*1/0.1*1
=10/0.1=100ml
Therefore volume of acid = 100ml
7 0
4 years ago
Can someone help?? This is really hard.
Sergeu [11.5K]

Answer:

See Explanation

Explanation:

Let us consider the first two reactions, the initial concentration of CO was held constant and the concentration of Hbn was doubled.

2.68 * 10^-3/1.34 * 10^-3 = 6.24 * 10^-4/3.12 * 10^-4

2^1 = 2^1

The rate of reaction is first order with respect to Hbn

Let us consider the third and fourth reactions. The concentration of Hbn is held constant and that of CO was tripled.

1.5 * 10^-3/5 * 10^-4 = 1.872 * 10^-3/6.24 * 10^-4

3^1 = 3^1

The reaction is also first order with respect to CO

b) The overall order of reaction is 1 + 1=2

c) The rate equation is;

Rate = k [CO] [Hbn]

d) 3.12 * 10^-4 = k [5 * 10^-4] [1.34 * 10^-3]

k = 3.12 * 10^-4  /[5 * 10^-4] [1.34 * 10^-3]

k = 3.12 * 10^-4/6.7 * 10^-7

k = 4.7 * 10^2 mmol-1 L s-1

e) The reaction occurs in one step because;

1) The rate law agrees with the experimental data.

2) The sum of the order of reaction of each specie in the rate law gives the overall order of reaction.

8 0
3 years ago
What is the end result <br> of diffusion?
Olenka [21]

Answer:

The End Result Of Diffusion Is An Equal Concentration, Or Equilibrium, Of Mocules On Both Sides Of The Membrane.

Explanation:

☺️ Hope It helps Ty.

3 0
3 years ago
"Two-thirty in the afternoon" is a measure of:<br><br> relative time<br> absolute time
ladessa [460]
The answer would be B) Absolute time.
5 0
3 years ago
Read 2 more answers
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