a batter hits a homerun in which the ball travels 110m horizontally with no appreciable air resistance. If the ball left the bat
1 answer:
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Answer:
The electric field at origin is 3600 N/C
Solution:
As per the question:
Charge density of rod 1,
Charge density of rod 2,
Now,
To calculate the electric field at origin:
We know that the electric field due to a long rod is given by:
Also,
(1)
where
K = electrostatic constant =
R = Distance
= linear charge density
Now,
In case, the charge is positive, the electric field is away from the rod and towards it if the charge is negative.
At x = - 1 cm = - 0.01 m:
Using eqn (1):
(towards)
Now, at x = 1 cm = 0.01 m :
Using eqn (1):
(towards)
Now, the total field at the origin is the sum of both the fields:
Answer:
Let's investigate the case where the cable breaks.
Conservation of angular momentum can be used to find the speed.
The projectile embeds itself to the ball, so they can be treated as a combined object. <u>The moment of inertia of the combined object is equal to the sum of the moment of inertia of both objects. </u>
where r is the length of the cable.
<u>After the collision, the ball and the projectile makes a circular motion because of the cable.</u> So, the force (tension) in circular motion is
The relation between linear velocity and the angular velocity is
So,
As can be seen, the maximum velocity for the projectile without breaking the cable is , where r is the length of the cable.