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Montano1993 [528]
2 years ago
11

Cho q1= 8.10 mũ -8C ; q2 = -8.10 mũ -8C . Đặt tại 2 điểm A và B cách nhau 6cm trong không khí . Xác định lực điện dung dịch lên

qo = 8.10 mũ -8C đặt tại : a. CA= 4cm , CB= 10cm b. CA=CB= 5cm c. CA= 6cm , CB= 6cm
Physics
1 answer:
olga nikolaevna [1]2 years ago
6 0

Answer:

‍♂️

Explanation:

‍♂️‍♂️‍♂️

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D is the correct answer!!
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Which result occurs during an exothermic reaction?
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3 0
1 year ago
if vector u has lenght 70 and direction 40 degrees, and vector v has length 85 and direction 335 degrees what is the length and
Anastaziya [24]

Answer:

Magnitude of resultant = 131.15

Direction of resultant = 3.97°

Explanation:

||u|| = 70

θ = 40°

\vec{u}_x=||u||cos\theta \\\Rightarrow \vec{u}_x=70cos40=53.62

\vec{u}_y=||u||sin\theta \\\Rightarrow \vec{u}_y=70sin40=44.99

||v|| = 85

θ = 335°

\vec{v}_x=||v||cos\theta \\\Rightarrow \vec{v}_x=85cos335=77.03

\vec{v}_y=||v||sin\theta \\\Rightarrow \vec{v}_y=85sin335=-35.92

Resultant

R=\sqrt{R_x^2+R_y^2}\\\Rightarrow R=\sqrt{(\vec{u}_x+\vec{v}_x)^2+(\vec{u}_y+\vec{v}_y)^2}\\\Rightarrow R =\sqrt{(70cos40+85cos335)^2+(70sin40+85sin335)^2}\\\Rightarrow R =131.15

\theta=tan^{-1}\frac{R_y}{R_x}\\\Rightarrow \theta=tan^{-1}\frac{70sin40+85sin335}{70cos40+85cos335}\\\Rightarrow \theta=tan^{-1}0.069=3.97^{\circ}

Magnitude of resultant = 131.15

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4 0
3 years ago
A 1000-kg whale swims horizontally to the right at a speed of 6.0 m/s. it suddenly collides directly with a stationary seal of m
Sphinxa [80]

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v = initial velocity of the seal before collision with the whale = 0 m/s

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inserting the above values in the equation

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Explanation:

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