The time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.
The given parameters;
<em>Mass of the first object, m1 = 1 kg</em>
<em>Mass of the second object, m2 = 5 kg</em>
The final velocity of the objects during the downward motion is calculated as follows;
The time of motion of the object from the given height is calculated as;
The time of motion of each object is independent of mass of the object.
Thus, the time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.
Learn more about time of motion here: brainly.com/question/2364404
0.33 . Equation is Force of friction equals normal force times coefficient of friction, so 6=18u. Divide 6 by 18
Answer:
Explanation:
given,
Radius of earth = 6400 Km
speed of a physics student in Miami, Florida, at latitude 26° = v
time period of rotation = 24 hour = 24 × 3600
= 86400 s
distance = speed × time
hence, the velocity of the student is equal to
Answer:
F = 1200 N
General Formulas and Concepts:
<u>Forces</u>
Newton's Second Law of Motion: F = ma
- F is force (in N)
- m is mass (in kg)
- a is acceleration (in m/s²)
Explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
<em>m</em> = 300 kg
<em>a</em> = 4 m/s²
<u>Step 2: Find Force</u>
- Substitute in variables [Newton's Second Law of Motion]: F = (300 kg)(4 m/s²)
- Multiply: F = 1200 N
Topic: AP Physics 1 - Algebra Based
Unit: Forces
